B- black allele;
b- brown allele;
The parental cross is true-breeding because both the male and the female are homo zygotes, so: BBx bb
The F1 generation will be all black heterozygote: Bb
The F2 generation will be between mice of the F1 generation and they all have the same genotype:Bb xBb
In this cross it would result in:
1/4 of the plants being black homozygote-BB 25%
2/4 of the plants being black heterozygote- Bb- 50%
1/4 of the plants being brown homozygote- bb- 25%
answer: 25%+25%=50% are homozygotes
Solid liquid gas science is key my g
Answer:
There must have two white genes to become white.
Explanation:
In order to a mouse to have white fur, both of their genes must be white. In the punnet square, you have a Black (BB) and a white (bb). If they have offspring, all of them have one black (Dominant) and one white (recessive). The black gene overpowers the white gene, so they come out black.
<span>Large changes in allele frequencies can occur in a short time - any changes in frequency, occurring as a result of random chance, would have a proportionally larger effect in a small population. </span>
Answer:
The population will decrease
Explanation:
The reason it will decrease is that the predators will be able to find the brown mice more easily in the snow then the white mice.
