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irinina [24]
3 years ago
13

What is the area of a triangle

Mathematics
1 answer:
777dan777 [17]3 years ago
8 0
The equation is one half times the base times the height.
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Find the perimeter use pi
balandron [24]
Since d x pi = circumference
I use 3.14 as pie

I did 9 x pi = 28.26 I DID NOT divide this by two because there are three half circles and 28.26 counts as two of them

Since there is another half circle I divide 28.26 by 2

28.26 + 14.13 = 42.39

Now plus the bottom length

42.39 + 9 = 51.39


Brainliest answer please?
8 0
3 years ago
Gabe read a total of 21 books with his book club over 7 months. After belonging to the book club for 22 months, how many books w
cestrela7 [59]

Answer:

66

Step-by-step explanation:

6 0
3 years ago
Please help!!<br> Thanks
Kitty [74]

1.5 because is 2 inches is 20 bags the it be 1 inch for 10 bags, so going half of 10 is 5 and 1 divided by 2 is .5... so add up the 10 bags and 5 bags to get an answer of 1.5 inches.

8 0
3 years ago
The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f
Sloan [31]

Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen  who carry a credit card balance.

The formula for the interval is:

p'₁±Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }

Z_{1-\alpha /2}= Z_{0.95}= 1.648

0.37±1.648*\sqrt{\frac{0.37*0.63}{1000} }

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂±Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }

0.48±1.648* \sqrt{\frac{0.48*0.52}{1000} }

0.48±1.648*0.016

[0.45;0.51]

With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: \sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015

Seniors: \sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0
3 years ago
A guidance counselor is studying test anxiety in freshman students. A random sample of 972 high school freshmen finds that 219 o
ArbitrLikvidat [17]

Answer:

The answer is B.

7 0
3 years ago
Read 2 more answers
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