Answer: The new ratio will be 1/4
Explanation: The initial ratio of losses to wins is 3 to 2. If we sum the numer of losses and wins 3 + 2 = 5 games, that means they loss 3 out of 5 games , and they win 2 out of 5 games.
So if they had won twice as many of the games, that is 2*2=4. And since the number of games is the same ( 5 ), then they would have won 4 games and loss only 1.
So the new ratio of losses to wins will be 1 to 4, or expressed in a fraction: 1/4
Consecutive integers = in this situation double-digit whole numbers
So as there are 3 of them let's say 2 are 11 because that would be the highest consecutive number so 11+11= 22 and 48-22=26 so the three have the ages of 11,11,26 and the oldest would be 26 ;)
Greetings!
To start this problem, let's first assign a variable for the missing, consecutive odd numbers. Since they are consecutive and odd, we add two.
<u>Proof:</u> <em>3-1=2, 5-3=2</em>
The first, consecutive, odd number: 
The second, consecutive, odd number: 
The third, consecutive, odd number: 
The fourth, consecutive, odd number: 
The sum of the values are equal to 3 times the sum of the first two numbers, of which this is equal to 35 less than the fourth number. Let's create an equation to simplify this:

Complete the operations inside the parenthesis:

Distribute the parenthesis (utilizing the distributive property)


Simplify both sides:

Add -6 and -x to both sides of the equation:


Divide both sides of the equation by 5:


If
is equal to -7:



The four numbers are:

I hope this helps!
-Benjamin