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3 years ago

Subtract. Eight-ninths minus one-third

Mathematics

2 answers:

Evgen [1.6K]3 years ago

4 0

Answer:

Five-ninths

Step-by-step explanation:

Since the denominators are different (9 and 3) we need to change one of them.

9 is divisible by 3 therefor we do not need to change Eight-ninths.

3 times 3 = 9, nine becomes the new denominator, but remember, whatever we do to the bottom (denominator), we must also do to the top (numerator).

1 times 3 = 3

Now the equation is 8/9 - 3/9, we must only subtract the numerators. The answer is 5/9.

Bingel [31]3 years ago

3 0

8/9 - 1/3

To subtract these two fractions, first find a common denominator.

The common denominator will be the

least common multiple for the two denominators.

In this case, the least common multiple of 9 and 3 is 9.

So to subtract, a denominator of 9 is needed in each fraction.

8/9 already has 9 in the denominator so it stays the same.

To get a 9 in the denominator of 1/3, multiply top and bottom by 3.

This gives us 3/9.

So we have 8/9 - 3/9 which is 5/9.

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Find the volume of the solid generated when R (shaded region) is revolved about the given line. x=6−3sec y, x=6, y= π 3, and

Dmitrij [34]

Answer:

$V=9\pi\sqrt{3}$

Step-by-step explanation:

In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).

The formula we will use for this problem is the following:

$V=\int\limits^b_a {\pi r^{2}} \, dy$

where:

$r=6-(6-3 sec(y))$

$r=3 sec(y)$

a=0

$b=\frac{\pi}{3}$

so the volume becomes:

$V=\int\limits^\frac{\pi}{3}_0 {\pi (3 sec(y))^{2}} \, dy$

This can be simplified to:

$V=\int\limits^\frac{\pi}{3}_0 {9\pi sec^{2}(y)} \, dy$

and the integral can be rewritten like this:

$V=9\pi\int\limits^\frac{\pi}{3}_0 {sec^{2}(y)} \, dy$

which is a standard integral so we solve it to:

$V=9\pi[tan y]\limits^\frac{\pi}{3}_0$

so we get:

$V=9\pi[tan \frac{\pi}{3} - tan 0]$

which yields:

$V=9\pi\sqrt{3}$ ]

6 0

4 years ago

a recycling bin is in the shape of a rectangular box find the height of the box if it's length is 18 ft its width is 8 feet and

OLEGan [10]

<h2>Answer:</h2>

The height of the box is:

4 ft.

<h2>Step-by-step explanation:</h2>

Let "h" denotes the height of the box.

Length of box is denoted by "l"

and breadth or width of box is denoted by "b"

We are given l=18 ft

b=8 ft.

Also we are given surface area of rectangular box= 496 ft²

As we know that the surface area of box is given by:

$Surface\ Area=2(lb+bh+hl)$

i.e.

$496=2(18h+8h+144)\\\\i.e.\\\\\\496=2(26h+144)$

Divide both side by 2.

$248=144+26h\\\\i.e.\\\\26h=248-144\\\\i.e.\\\\26h=104$

on dividing both side by 26 we get:

$h=4$

Hence, the height of the box is:

4 ft.

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snow_lady [41]

Answer:

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