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ch4aika [34]
4 years ago
15

How do you know which variable is the independent variable and which variable is the dependent variable in a real-world situatio

n solving involving an arithmetic sequence?​
Mathematics
1 answer:
postnew [5]4 years ago
7 0
A variable (often denoted by x ) whose variation does not depend on that of another.


a variable (often denoted by y ) whose value depends on that of another.

This is for math of corse but we can use this to answer it, all you have to do is find the x which is time, then y is just the opposite of time, hope this helps. Let me know if you have any questions or want me to help you on a question I know my answer was a bit veg.
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Tom used twenty gallons of water to
oksano4ka [1.4K]

Answer:

y=20x + 40x

Step-by-step explanation:

8 0
4 years ago
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I am wondering if the answer to this question is Table B. At x = 1, f'(x) = 1/2. At x = 2, f'(x) = 3. Does this mean that, betwe
noname [10]
I agree. The answer is choice B

=========================================================

f ' (1) is shown to be positive
f ' (2) is shown to be positive as well
There are no critical values between x = 1 and x = 2, so f ' (x) is positive on the interval 1 < x < 2, so f(x) is increasing on this interval

All of this points to either choice A or choice B

--------------------------------

Similarly, 
f ' (3) is negative
f ' (4) is negative
so f ' (x) is negative where 3 < x < 4 due to no other critical values being between x = 3 and x = 4

Based on these facts alone, the answer is either choice B or choice D

But we know that it can't be choice D as we determined it was between A and B. This rules out choice D

So all that's left is choice B
6 0
4 years ago
This hyperbola is centered at theorigin. Find its equation.Foci: (-2,0) and (2,0)Vertices: (-1,0) and (1,0)
beks73 [17]

SOLUTION

From the question, the center of the hyperbola is

\begin{gathered} (h,k),\text{ which is } \\ (0,0) \end{gathered}

a is the distance between the center to vertex, which is -1 or 1, and

c is the distance between the center to foci, which is -2 or 2.

b is given as

\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}

But equation of a hyperbola is given as

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

Substituting the values of a, b, h and k, we have

\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}

Hence the answer is

\frac{x^2}{1}-\frac{y^2}{3}=1

5 0
1 year ago
I need help with this awnser
Musya8 [376]
The 3rd statement is true
6 0
3 years ago
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Please help me answer the question
Rufina [12.5K]

Answer:

y=-x+2

Step-by-step explanation:

The slope-intercept form is y=mx+b where m is the slope and b is the y-intercept.

From the graph, we can see that the y-intercept is at (0,2) so the equation becomes y=mx+2.

Other points on the graph include (1,1) and (2,0). Plugging (1,1) into the slope-intercept equation, we get 1=(m)1+2. Solving this will give us m=-1.

We can confirm this by plugging m=-1 into the equation along with the point (2,0); 0=(-1*2)+2. It checks out!

So our final equation in slope-intercept form will be y=-x+2

4 0
3 years ago
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