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ch4aika [34]
3 years ago
15

How do you know which variable is the independent variable and which variable is the dependent variable in a real-world situatio

n solving involving an arithmetic sequence?​
Mathematics
1 answer:
postnew [5]3 years ago
7 0
A variable (often denoted by x ) whose variation does not depend on that of another.


a variable (often denoted by y ) whose value depends on that of another.

This is for math of corse but we can use this to answer it, all you have to do is find the x which is time, then y is just the opposite of time, hope this helps. Let me know if you have any questions or want me to help you on a question I know my answer was a bit veg.
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Helga [31]

<h3>They are 268 miles far apart after 4 hours</h3>

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

<u>Given :</u>

v₁ = 30 mph due east

v₂ = 60 mph due south

t = 4 hours

<u>Unknown :</u>

displacement = d = ?

<u>Solution :</u>

d_1 = v_1 \times t

d_1 = 30 ~ mph \times 4 ~ h

d_1 = \boxed {120 ~ miles}

d_2 = v_2 \times t

d_2 = 60 ~ mph \times 4 ~ h

d_2 = \boxed {240 ~ miles}

d^2 = (d_1)^2 + (d_2)^2

d^2 = 120^2 + 240^2

d^2 = 72000

d = \sqrt{72000}

d = 120\sqrt{5} ~ miles

d \approx \boxed {268 ~ miles}

<h2>Conclusion :</h2><h3>They are 268 miles far apart after 4 hours</h3>

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

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