What is the value of the expression 2.6 x 10 to the 9th power over 1.3 x 10 to the 2nd power?

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

4 0

2.6 * 10^9
-------------
1.3 * 10^2

2.6 / 1.3 = 2 and 10^9 / 10^2 = 10^7

so the answer is 2 * 10^7

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If 9p=5q which is the correct ratio of p:q

tatyana61 [14]

Answer: LHS = RHS

Step-by-step explanation:

Heya!!

Here, we need to compare the LHS and RHS

So, here is the solution -

(9p-5q)²+ 180 pq = (9p+5q)

LHS

= (9p-5q)²+ 180 pq

= 81 p² + 25 q² + 90 pq + 180 pq

= (9p - 5q) ²

RHS = (9p - 5q) ²

Hence, proved => LHS = RHS

Hope it helps!

4 0

3 years ago

Read 2 more answers

HELP!!!In the expression 100 a/b, if a is greater than b, which statements are true? b ≠ 0. Select all that apply.

MAXImum [283]

Answer:

$\large\boxed{\text{The expression is equal to}\ \sqrt[b]{100^a}}\\\boxed{\text{The expression is greater than 100}}$

Step-by-step explanation:

$a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\text{True statement:}\\\\100^\frac{a}{b}=\sqrt[b]{100^a}\\\\a>b\to\dfrac{a}{b}>1\to\dfrac{a}{b}=1\dfrac{a-b}{b}\\\\100^\frac{a}{b}=100^{1\frac{a-b}{b}}=100^{1+\frac{a-b}{b}}=100^1\cdot100^\frac{a-b}{b}=100\sqrt[b]{100^{a-b}}\\\\a>b\to a-b>0\to100^{a-b}>1\\\\\text{Therefore}\ 100\sqrt[b]{100^{a-b}}>100$