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3 years ago

Segment AE is a median for Triangle ABC.

Mathematics

1 answer:

Shalnov [3]3 years ago

4 0

Step-by-step explanation:

$BC = BE + CE...(\because B-E-C) \\ \\ \therefore \: BC = 3x - 5 + x + 1 \\ \\ \therefore \: BC = 4x - 4 \\ \\ \huge \red{ \boxed{ \therefore \: BC = 4(x - 1)}}$

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Identify the sampling designs that use voluntary response sampling. Check all that apply.

Marta_Voda [28]

Step-by-step explanation:

A voluntary response sample is defined as a type of sample made up of self-chosen participants. These participants volunteer to take part in different research studies to share their opinions on topics that interest them. A voluntary response sample is made up of persons who volunteer to take research surveys.

3 0

2 years ago

Read 2 more answers

Practice Writing Composite Functions Given: f(x) = x - 7 and h(x) = 2x + 3 Write the rule for h(f(x)).

Setler79 [48]

Answer:

Step-by-step explanation:

f(x) = x - 7

h(x) = 2x + 3

To find h(f(x)) substitute f(x) into h(x) that's replace every x in h(x) by f(x)

That's

h(f(x)) = 2(x - 7) + 3

h(f(x)) = 2x - 14 + 3

We have the final answer as

Hope this helps you

6 0

2 years ago

Someone find x !!!!!!

BartSMP [9]

14. 128
15.25
16.90
those should be right

6 0

2 years ago

A single microvillus is a rod-like structure that is 1.0 μm in height. It has a hemispherical top approximately 0.1 μm in diamet

gregori [183]

Answer:

so, the figure here is a cylinder with a semi sphere on the top, we know the height of whole structure, and the radius of the semi sphere, which is the same as the radius of the cylinder (you can see it because the radius of the semisphere is constant, and you can thin on it as half a sphere over a cylinder).

First, the cylinder will be the structure without the semi sphere, so his height will be te total height minus the radius of the semi sphere, which is 0.9μm.

so now we know the height and the radius of the cylinder, the surface or the sides of it is 2*3.14*r*h = 2*3.14*0.9μm*0.1μm = 0.5662 $μm^{2}$ .

3 0

3 years ago

Suppose that the sitting back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 24.4 in.

solong [7]

Answer:

$P(X \geq 26.6) = 0.0336$ , which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 24.4, \sigma = 1.2$