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inna [77]
3 years ago
8

A parachutist's rate during a free fall reaches 45 meters per second. What is this rate in feet per second? At this rate, how ma

ny feet will the parachutist fall during 15 seconds of free fall? In your computations, assume that 1 meter is equal to 3.3 feet. Do not round your answers.
Mathematics
1 answer:
Alina [70]3 years ago
8 0
198 feet..........1 meter 
<span>------------- X-------------- </span>
<span>1 second.......3.3 feet </span>

<span>198 </span>
<span>----- meters per second </span>
<span>3.3 </span>

<span>60 meters per second.......ANSWER </span>

<span>60 m/sec X 15 sec = 900 feet.......ANSWER </span>

<span>If you have questions on this or any other math problem feel free </span>
<span>to let me know how to contact you.......Read Below....... </span>

<span>I tutor free online since moving to France from Florida in June 2011. </span>
<span>I still tutor by skype to students in Florida and starting to gain more world-wide. </span>
<span>Hope this is most helpful and you will continue to allow me to tutor you. </span>
<span>If you dont fully understand or have a question PLEASE let me know </span>
<span>how to contact you so you can then contact me directly with any math questions. </span>
<span>If you need me for future tutoring I am not allowed to give out my </span>
<span>info but what you tell me on ***how to contact you*** is up to you </span>
<span>Been a pleasure to serve you Please call again </span>
<span>Robert Jones.............f </span>
<span>"Teacher/Tutor of Fine Students" </span>
<span>A PRESENT FOR YOU </span>
<span>Ask someone to write a number, say a five-digit number. </span>
<span>(Can be a 2-digit.....3-digit.....4-digit....ect..... </span>
<span>Suppose the number written is </span>
<span>57836 </span>
<span>Now, without showing the asker, you write a number on </span>
<span>a sheet of paper and keep it folded. You have to write the </span>
<span>number by subtracting 2 from the above number and </span>
<span>adding 2 in front which will be.... </span>
<span>257834 </span>
<span>Next, ask the person to write another five-digit number </span>
<span>below his original number. Suppose he writes 37589. </span>
<span>So you now have... </span>
<span>57836 </span>
<span>37589 </span>
<span>Now you write a five-digit number below it in such a </span>
<span>way that each digit is 9 minus digit above. You now have... </span>
<span>57836 </span>
<span>37589 </span>
<span>62410 </span>
<span>Ask the person to add one more 5-digit number. If he </span>
<span>adds 54732, you add below it 45267. Note that you decided </span>
<span>the number by subtracting each of his digit from 9. </span>
<span>Thus, you now have..... </span>
<span>57836 </span>
<span>37589 </span>
<span>62410 </span>
<span>54732 </span>
<span>45267 </span>
<span>Next, ask him to add all the number and he gets 257834 </span>
<span>Show him the number which you had written as an answer </span>
<span>to this addition earlier in the folded paper and surprise him.</span>
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What is the measurement of 2 and 11​
vagabundo [1.1K]

<2=40° <11=60°

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3 years ago
A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin
Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

T_1cos\theta_1-T_2cos\theta_2=0           (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

T_1sin\theta_1+T_2sin\theta_2-W=0               (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2

Then, you sum the equations:

T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2        (3)

Next, you use the following identity:

sin^2\theta+cos^2\theta=1

and you obtain in the equation (3):

T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°

With this values you can calculate the value of the another angle, by using the equation (1):

\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0
2 years ago
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