Median: 29
Range: 25
IQR: 14.5
Explanations:
**Median:**
(To find the median, we need to first order all the elements)
Ordered —> 15, 18, 18, 20, 23, 28, 30, 33, 33, 34, 38, 40
(Since there are an even number of elements, we need to add the two elements in the middle and divide by 2)
Median = (28 + 30)/2 = 58/2 = 29
**Range:**
(To find the range, you just have the subtract the smallest one from the largest)
Range = 40 - 15 = 25
**IQR:**
First half of elements —> 15, 18, 18, 20, 23, 28
Second half of elements —> 30, 33, 33, 34, 38, 40
Q1 (Quartile 1) = Median of first half = (18 + 20)/2 = 38/2 = 19
Q3 (Quartile 3) = Median of second half = (33 + 34)/2 = 67/2 = 33.5
IQR = Q3 - Q1 = 33.5 - 19 = 14.5
Pls help its due tomorrow
The answer would be 3 hope helps
Let's call that number x, twice the number will be 2x, sum of it and 5 is, 2x+5. So if this expression is at most 15, it means, it can be only less than 15 and equal to 15. Let's show this as an inequality.
Let's solve.
![x\quad \in \quad \left[ -\infty ,5 \right]](https://tex.z-dn.net/?f=x%5Cquad%20%5Cin%20%5Cquad%20%5Cleft%5B%20-%5Cinfty%20%2C5%20%5Cright%5D%20)
If the number is a natural number. The values it can take is,
![x\quad \in \quad \left[ 0,1,2,3,4,5 \right]](https://tex.z-dn.net/?f=x%5Cquad%20%5Cin%20%5Cquad%20%5Cleft%5B%200%2C1%2C2%2C3%2C4%2C5%20%5Cright%5D%20)
The correct answer is D
Hope this helps!
