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4 years ago

12

Write the number that answers the riddle use the chart a model for my number has 6 ones blocks,2 hundreds block,and 3 tens block

s. What number am I?

1 answer:

Oksanka [162]4 years ago

4 0

I believe it's 236 if I understand the question correctly

You might be interested in

2-step equations Solve: 1/4n+7=10<br>show the steps

Bingel [31]

Answer:

$n = 12$

Step-by-step explanation:

$\frac{1}{4}n+ 7 = 10$

$\frac{1}{4}n = 3$

$n = 12$

Hope this helps :)

6 0

3 years ago

[[ CHECK THIS ASAP PLEASE ]] <br> Is my answer correct or no?

Natalija [7]

the shape is NOT a rhombus, because opposite sides are parallel but not all sides are congruent in length.

This shape is instead a parallelogram, where opposite sides are parallel but all sides do not have to be the same length

if 2 pairs of opposite sides are parallel, then opposite sides must be congruent, changing the angles will create nonparallel opposite sides that are unequal length and neither a parallelogram nor rhombus

8 0

3 years ago

There is a paint chip on the edge of a gear for a music box. It rotates to (−7, 3) during one song when represented graphically.

lys-0071 [83]

I hope this helps you

6 0

3 years ago

How many different 7-place license plates are possible when 3 of the entries are letters and 4 are digits? Assume that repetitio

timofeeve [1]

Answer:

There are 6,151,600,000 different 7-place license plates are possible when 3 of the entries are letters and 4 are digits,

Step-by-step explanation:

For each of the entries which are letters, there are 26 possible outcomes.

For each of the entries which are digits, there are 10 possible outcomes.

These outcomes can be permutated.

For example, ABC1234 is a different outcome than A1B2C34. This means that we need to use the permutations formula.

The number of permutations of n, divided into two groups of size a and b, is:

$P_{a,b}^{n} = \frac{n!}{a!b!}$ .

In this problem, we have a permutation of 7, divided into a group of 4(digits) and 3(letters).

How many different 7-place license plates are possible when 3 of the entries are letters and 4 are digits?

This is $P_{3,4}^{7}*(26)^{3}*10^{4} = 35*(26)^{3}*10^{4} = 6,151,600,000$

There are 6,151,600,000 different 7-place license plates are possible when 3 of the entries are letters and 4 are digits,

7 0

3 years ago

The lengths of the sides of a triangle are in the extended ratio 44 : 55 : 77. the perimeter of the triangle is 6464 cm. what

joja [24]

44x + 55x + 77x = 6,464 centimeters.
x = <span> <span> <span> 36.7272727273 </span>

Therefore the sides are
44*</span></span><span><span>36.7272727273 = 1,616 </span>
55*</span><span>36.7272727273 </span>= 2,020
77* <span> <span> <span> 36.7272727273 </span> </span> </span> = 2,828

OR maybe that's another of those infamous Brainly typos.

4x + 5x + 7x = 64 centimeters.
x = 8

Therefore the sides are
4*8 = 32
5*8 = 40 and
7*8 = 56 centimeters

6 0

3 years ago