Answer:
Step-by-step explanation:
We first need to define a couple of variables. Let s = the cost of 1 squash and z = the cost of 1 zucchini.
Now lets translate the words into algebra:
"The cost of 5 squash and 2 zucchini is $1.32" ===> 5s + 2z = 1.32
"Three squash and 1 zucchini cost $0.75" ===> 3s + z = 0.75
There are several ways to solve systems of equations. Let's use substitution. We can find what z equals in terms of s by manipulating the second equation:
3s + z = 0.75
-3s -3s
------------ -------------
z = -3s +0.75
Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:
5s + 2(-3s + 0.75) = 1.32
Can you handle it from here?
(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)
Answer:
Is it too late to answer this?
Step-by-step explanation:
Answer:
-2
Step-by-step explanation:
X1 Y1 X2 Y2
(-15, 30) (7, -14)
Y2-Y1 = -14-30 = -44 = -2
———————————————
X2-X1 = 7-(-15)= 22 = 1
y/x =k
13/9 = 1.4444444
39/27=1.4444444
104/72=1.4444444
k =13/9 = 1 4/9
this is direct variation with a constant of 13/9 or 1 4/9
Answer:
80
Step-by-step explanation:
0
plz...
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