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MrMuchimi
3 years ago
15

Nine more than the quotient of two and a number x xx.

Mathematics
2 answers:
leonid [27]3 years ago
5 0

2/x + 9 is the answer

never [62]3 years ago
3 0

Answer:

9 + \frac{2}{x}

Step-by-step explanation:

I guess this exercise is about translating the problem directions to math language...

The first part states "nine more than...". Usually, "more than" can be translated to addition, in this case the addition of 9 and an expression that needs to be determinated. This can be translated to math language as:

9 + ...         (1)

The second part of the statement says "the quotient of two and a number x". Quotient means division, in this case the division of 2 and x. Then we have:

... + \frac{2}{x}          (2)

Putting (1) and (2) together, the answer is

9 + \frac{2}{x}

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One mixture contains 6 fluid Ounces of water and 10 fluid Ounces of vinegar. A second mixture
Nadya [2.5K]

Answer:

The mixtures are not proportional.

3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture.

its =3

Step-by-step explanation:

The one mixture contains 6 fluid ounces and 10 fluid ounces of water and vinegar respectively.

Therefore, the ratio of water to vinegar in the first mixture is 6 : 10 = 3 : 5

Now, a second mixture contains 9 fluid ounces of water and 12 fluid ounces of vinegar.

Hence, the ratio of water to vinegar in the second mixture is 9 : 12 = 3 : 4

Therefore, the mixtures are not proportional.

Therefore, we have to add x fluid ounces of vinegar to the second mixture to make it in the ratio of 3 : 5.

So,

⇒ 12 + x = 15

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5 0
2 years ago
Find the x- and y-intercepts of the following equation:<br> 2x+3y=-24
Ilya [14]

Answer:

Algebra 

 Topics 

How do you find the intercepts of x2y−x2+4y=0?

Algebra  Graphs of Linear Equations and Functions  Intercepts by Substitution

2 Answers

Gió

Mar 24, 2015

For the intercepts you set alternately x=0 and y=0 in your function:

and graphically:

Answer link

Alan P.

Mar 24, 2015

On the X-axis y=0

So

x2y−x2+4y=0

becomes

x2(0)−x2+4(0)=0

→−x2=0

→x=0

On the Y-axis x=0

and the original equation

x2y−x2+4y=0

becomes

(0)2y−(0)2+4y=0

→y=0

The only intercept for the given equation occurs at (0,0)

Answer link

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Answer:

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Step-by-step explanation:

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