The right fraction represents the percentage; 42 over 100 (100 is the total), or 0.42.
The left fraction is the part number over the whole number. The whole number is unknown, so we use 'x'.
Your answer is 75.
What function/equation is best for this
2 answers:
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The right fraction represents the percentage; 42 over 100 (100 is the total), or 0.42.
The left fraction is the part number over the whole number. The whole number is unknown, so we use 'x'.
Your answer is 75.
Answer:
The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.
Step-by-step explanation:
Given:
Maximum safe-weight of 37 cars = 82 tons
∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)
Mean weight of 1 car (μ) = 2 tons
Standard deviation of 37 cars = 0.8 tons
So, standard deviation of 1 car is given as:
Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?
The sample is normally distributed (Assume)
Now, let us determine the z-score of the mean weight.
The z-score is given as:
Now, finding P(x > 2.22) is same as finding P(z > 1.69).
From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.
But we need the area under the curve for z > 1.69.
So, we subtract from the total area. Total area is 1 or 100%.
So,
Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.
For this case we have the following equation:
Where,
d: the distance they can see in thousands
h: their eye-level height in feet
For Kaylib:
For Addison:
Subtracting both distances we have:
Answer:
B. 2√2 mi
Where,
d: the distance they can see in thousands
h: their eye-level height in feet
For Kaylib:
For Addison:
Subtracting both distances we have:
Answer:
B. 2√2 mi