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Eduardwww [97]
4 years ago
8

What is an equation of the line that passes through the points (-7, -7) and(-5, -3)?​

Mathematics
2 answers:
antoniya [11.8K]4 years ago
6 0
What they said !!!!!!
Feliz [49]4 years ago
4 0

Answer:

y = 2x + 7

Step-by-step explanation:

We can use slope-intercept form.

y = mx + b

slope m = (y2- y1)/(x2-x1) = (-3-(-7))/(-5 -(-7)) = 4/2 = 2

m = 2

y = 2x +b

To find b we can use one of the points for example (-5,-3)

-3 = 2*(-5) + b

-3 = - 10 + b

b = 7

y = 2x + 7

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How to solve a system of three equations with substitution
zloy xaker [14]

Answer:

Usually there are the variables x y z but it doesn't matter what they are.

Step-by-step explanation:

First choose your first variable to solve. Find x by putting all the numbers and variables to one side.

once you found x substitute the answer for x in all the equations. Next find y and substitute your answer in all the equations again.

Once you have solved 2 variables then you are able to solve z.  

If you have questions please feel free to ask in the comments below.

4 0
3 years ago
Find the volume of the figure below. Leave answer in terms of t. Round to the nearest hundredth if necessary.
Vinil7 [7]

Answer:

36π

Step-by-step explanation:

d= 6 in

r= d/2=6/2= 3 in

volume of sphere= 4/3πr^3

=4/3 ×π×3^3

=36π in^3

8 0
3 years ago
carly tutors stufents in math on the weekends and offers both thirty minute and sixtyminute sessions she earns $15for each thirt
Ronch [10]

Answer:

X=7

Step-by-step explanation:

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6 0
3 years ago
Which function below is the inverse of f(x) = x2 − 36? x squared over 36 ą6square root of x 1 over quantity x squared minus 36 ą
Hitman42 [59]
The answer would be <span><span>f<span>−1</span></span><span>(x)</span></span>=<span>√<span>36+x</span></span>,<span>−<span>√<span>36+<span>x. I didn't know it in word form :(</span></span></span></span>
4 0
3 years ago
Find all solutions to the equation.<br><br> cos2x + 2 cos x + 1 = 0
yanalaym [24]
For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
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</span>3 tan^2 x = 1.

So x = pi/2, pi/2 + pi = 3pi/2.

5 0
3 years ago
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