Answer:
A
Step-by-step explanation:
I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,
So, 
So, 
Hope this helps you!
The answer is A because the square root function needs to be greater than or equal to zero bc the circle is filled and you can’t have a negative radical. It’s also choice A because the -1 is outside of the radical which means it’s being translated downwards from the parent function. Hope that helps ;-;
Answer:
Step-by-step explanation:
i can help
Step 1
4( − 11) = 15 − 4 Solving
Step 2
4( − 11) = 15 − 4 Simplify
15-4
-44=11
Answer
Unique solution
Hope this helps
Answer:
y = (x+3)^2 -1
Step-by-step explanation:
The vertex form of the equation is
y = a(x-h)^2 +k where (h,k) is the vertex
The vertex is (-3,-1)
y = a(x- -3)^2 -1
y = a(x+3)^2 -1
Pick another point (-2,0) and substitute it into the equation
0 = a(-2+3)^2 -1 to find a
0 =a(1)^2 -1
0 = a-1
1 = a
y = (x+3)^2 -1
