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3 years ago

What percent of 300 is 600

Mathematics

2 answers:

Ulleksa [173]3 years ago

7 0

200% .-. Is your answer

sveticcg [70]3 years ago

4 0

600, because it's 2 times as much as 300, it would be 200%

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In the figure below, segment AC is congruent to segment AB.

sattari [20]

Answer:

Option B is correct.

Angle DAC is congruent to angle DAB

Step-by-step explanation:

Given: Segment AC is congruent to segment AB.

In ΔABD and ΔACD

$AB \cong AC$ [Given]

[Congruent sides have the same length]

AB = AC [Side]

AD = AD [Common side]

$\angle DAC =\angle DAB$ [Angle]

Side Angle Side(SAS) Postulate states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.

Then by SAS,

$\triangle ABD \cong \triangle ACD$

By CPCT [Corresponding Parts of congruent Triangles are congruent]

then;

$\angle ABD \cong \angle ACD$

therefore, only statement which is used to prove that angle ABD is congruent to angle ACD is: Angle DAC is congruent to DAB

4 0

4 years ago

Read 2 more answers

Select the pair of equations whose graphs are perpendicular.

viktelen [127]

$k:\ y=m_1x+b_1\ \ \ \ and\ \ \ \ l:\ y=m_2x+b_2\\ \\the\ line\k\ is\ perpendicular\ to\ the\ line\ l\ \ \ \Leftrightarrow\ \ \ m_1\cdot m_2=-1\\----------------------------\\\\A.\\2y=-3x+5\ \ \Rightarrow\ \ \ y=- \frac{3}{2} x+2.5\ \ \Rightarrow\ \ m_1=- \frac{3}{2} \\\\2x+3y=4\ \ \Rightarrow\ \ 3y=-2x+4\ \ \Rightarrow\ \ y=- \frac{2}{3}x+1 \frac{1}{3} \ \ \Rightarrow\ \ m_2=- \frac{2}{3} \\\\m_1\cdot m_2=- \frac{3}{2} \cdot (- \frac{2}{3})=1 \neq -1$

$B.\\5x-8y=9\ \ \Rightarrow\ \ -8y=-5x+9\ \ \Rightarrow\ \ \ y= \frac{5}{8} x-1 \frac{1}{8} \ \Rightarrow\ \ m_1= \frac{5}{8} \\\\12x-5y=7\ \Rightarrow\ \ -5y=-12x+7\ \ \Rightarrow\ \ y= \frac{12}{5}x-1 \frac{2}{5} \ \ \Rightarrow\ \ m_2= \frac{12}{5} \\\\m_1\cdot m_2= \frac{5}{8} \cdot \frac{12}{5}= \frac{3}{2} \neq -1$

$C.\\y=2x-7\ \ \Rightarrow\ \ m_1=2 \\\\x+2y=3\ \Rightarrow\ \ 2y=-x+3\ \ \Rightarrow\ \ y= -\frac{1}{2}x+1 \frac{1}{2}\ \ \Rightarrow\ \ m_2=- \frac{1}{2} \\\\m_1\cdot m_2= 2 \cdot (- \frac{1}{2})= -1\ \ \Rightarrow\ \ y=2x-7\ \ \ \ \perp\ \ \ \ x+2y=3$

$
D.\\x+6y=8\ \ \Rightarrow\ \ 6y=-x+8\ \ \Rightarrow\ \ \ y=- \frac{1}{6} x+1 \frac{1}{3}\ \ \Rightarrow\ \ m_1= -\frac{1}{6} \\\\y=2x-8\ \Rightarrow\ \ m_2= 2 \\\\m_1\cdot m_2= -\frac{1}{6} \cdot2=- \frac{1}{3} \neq -1$

7 0

3 years ago

Multiple Choice: Please select the best answer and click "submit."

Georgia [21]

D. None of the above. Exponential decay implies constantly decreasing prices, i.e, f'(x) < 0 for all x.

7 0

3 years ago

Read 2 more answers

Helppppp me please heheheh

viva [34]

Joe nuts yah feel me lol because

4 0