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3 years ago

5

Pentagon ABCDE and pentagon A'B'C'D'E' are shown on the coordinate plane below:

1 answer:

s2008m [1.1K]3 years ago

7 0

Answer:

<h2>The third option is correct.</h2>

Step-by-step explanation:

The line D'E' is parallel to the y-axis.

Hence, it is clear that the image is reflected across the y-axis.

If you see closely the given image, you can see that the y ordinates of each point of the Pentagon has shifted 8 points towards the positive direction of y-axis.

Hence, the transformation for the y-coordinates will be Y = y + 8.

Now if you check the transformation for the x-coordinates, you will observe that the coordinates of D and E will be lie on x = -1. After reflection, they will lie on x = 1.

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Studentka2010 [4]

Answer:

Step-by-step explanation:

x1 = 0.5 x2 = -0.4 y1 = 1.3 y2 = -1.3

$\sqrt{(x2 - x1)^{2}+(y2 - y1)^{2}$

$\sqrt{(-0.4 - 0.5)^{2}+(-1.3 - 1.3)^{2}$

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3 years ago

Find the perimeter of the triangle with vertices A(negative 2,2,3), B(4,negative 4,3), and C(7,6,4).

gayaneshka [121]

Answer:

$P\approx 28.872\,\text{units}$

Step-by-step explanation:

We are given coordinates of each of the vertices of the triangle ABC, hence we can use the distance formula to find the lengths of each of the side.

the distance formula is generally written as:

$r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

for the side AB: A(-2,2,3) and B(4,-4,3)

$AB = \sqrt{(-2-4)^2+(2-(-4))^2+(3-3)^2}$

$AB = \sqrt{(-6)^2+(6)^2+(3-3)^2}$

$AB = \sqrt{72}$

for the side BC: B(4,-4,3) and C(7,6,4)

$BC = \sqrt{(4-7)^2+((-4)-6)^2+(3-4)^2}$

$BC = \sqrt{110}$

for the side CA: C(7,6,4) and A(-2,2,3)

$CA = \sqrt{(7-(-2))^2+(6-2)^2+(4-3)^2}$

$CA = \sqrt{98}$

Now we all the sidelengths:

to find the perimeter we need to just sum the three side lengths:

$P = AB + BC + CA$

$P = \sqrt{72} + \sqrt{110} + \sqrt{98}$

$P\approx 28.872\,\text{units}$

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Step-by-step explanation:

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Step-by-step explanation:

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4 years ago

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