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2 years ago

I know the answer but plz explain it. 5:3 × 6:2

1 answer:

3 0

5:3 x 6:2 can also be written as a fraction
5/3 x 6/2
Multiply across
30/6
Simplify
5/1
Rewrite
5:1 is your answer, or if your teacher does not want it simplified, 30:6

Hope I helped! :)

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In △ABC, G is the centroid. If CG=12 find CD.

VladimirAG [237]

Answer:

CD = 24

Step-by-step explanation:

If G is the centroid, then CG = GD. (12 = 12)

Since CD is CG and GD combined, we would just add these two numbers to find the total length of CD.

CG + GD = CD

12 + 12 = 24

5 0

2 years ago

Plz need help like now plz

nika2105 [10]

T) -7x+10y=20. M) -3x+y=-2 - ,
2(8x-5y)=35(2) -1(x+y)=-6(-)

-7x+10y=20. -3x+y=-2
16x-10y=70. -x-y=6

9x=90. -4x=4
[x=10] [x= -1]

-7(10)+10y=20. -3(-1)+y=-2
-70+10y=20. 3+y=-2
10y=90. [y= -5]
[y=9]

7 0

3 years ago

Multiply. (2.5 times 10^-8) (9 times 10^-10)

Lorico [155]

The complete answer is 2.25E-17

but I think it may be A

8 0

3 years ago

I’m a bit stuck on the second part of what y = x, can someone help me?

marissa [1.9K]

The answer should be 3, -1

4 0

2 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago