What is the missing constant term in the perfect square that starts with x2 + 10x ?

Mathematics

1 answer:

kirza4 [7]3 years ago

7 0

Answer:

Okay so I am assuming you mean the third part?

Step-by-step explanation:

Pretty simple. So you see that the varible x^2 does not have a number in front of it, so there is no extra dividing.

A formula for a perfect square is (x^2)+2xy+y^2

Take 10 and divide it by 2.

10/2=5

You have Y. Finding the third part is squaring Y.

5^2=25

Therefore, the third part of the perfect square is 25. If you want to find Y, look at the stuff above.

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Answer:

The company must sell 60 or 70 items to obtain a weekly profit of 200.

Step-by-step explanation:

The profit is the difference between the revenue and the cost of a given task, therefore:

$\text{profit} = R - C\\\text{profit} = 66*x - 0.2*x^2 - (40*x + 640)\\\text{profit} = 66*x - 0.2*x^2 - 40*x - 640\\\text{profit} = - 0.2*x^2 + 26*x - 640$

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$-0.2*x^2 + 26*x - 640 = 200\\-0.2*x^2 + 26*x -840 = 0\text{ } *\frac{-1}{0.2}\\x^2 -130 + -4200 = 0\\x_{1,2} = \frac{-(-130) \pm \sqrt{(-130)^2 - 4*1*(-4200)}}{2*1}\\x_{1,2} = \frac{130 \pm \sqrt{16900 + 16800}}{2}\\x_{1,2} = \frac{130 \pm \sqrt{100}}{2}\\x_{1,2} = \frac{130 \pm 10}{2}\\x_{1} = \frac{130 + 10}{2} = \frac{140}{2} = 70\\ x_{2} = \frac{130 - 10}{2} = \frac{120}{2} = 60$