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zalisa [80]
4 years ago
13

4m^3 over 3m^2n * 9n^2 over 30^2n^2

Mathematics
1 answer:
WARRIOR [948]4 years ago
8 0
Interrpretation:

4m^3                 9n^2
----------- *      ---------------  =
3m^2 n          30 m^2 n^2


        4m            3                    4                 2
=   --------- *   ------------ =    ----------- = -------------
        3n           10 m^2         10 n m          5 nm

Answer:

     2
----------
   5nm
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mariarad [96]
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1) The angle of elevation is the angle between the horizontal and the light of sight from the object to the observer (see picture 1).

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3) The table shows units in jya(θ<span>°). Jya is a Sanskrit (ancient Indian language) word. It stands for the length of half of a chord that connects two endpoints of a circle (kinda confusing and more information than you need to know - but it's the green line in picture 2).
What's important is: </span>jya(θ°) = r*sin(θ°)



Now let's tackle the problem:
1) You know that the angle of elevation is 67.5°. Using the chart, the only important value is the second from the bottom. jya(67.5°) = 3177. 

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The math is a bit weird, but you're basically multiplying sine by the apparent distance 1AU to get the apparent height, instead of multiplying sine by the estimated height r = 3438. Dividing 3177 by 3438 gives you sin(67.5°). Then multiplying sin(67.5°) by the apparent hypotenuse, 1AU, gives you the apparent height. That's how I'm understanding it!

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Semmy [17]

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