Question

Write the quadratic equation whose roots are 6 and 4, and whose leading coefficient is 4.

Answer 1

$\bf \begin{cases} x = 6\implies &x-6=0\\ x= 4\implies &x-4 = 0 \end{cases}\qquad \implies (x-6)(x-4)=\stackrel{y}{0} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\mathbb{F~~O~~I~~L}}{x^2-10x+24 = 0}\implies \stackrel{\textit{now we add a common factor of 4}~\hfill }{4(x^2-10x+24)=0\implies 4x^2-40x+96=y}$