All categories

4 years ago

Can somebody solve this? Thanks

Mathematics

2 answers:

Tatiana [17]4 years ago

7 0

The answer to this problem is 177

goldfiish [28.3K]4 years ago

3 0

Answer: 117

if angle BCD=27 cause its a smaller angle. smaller than 90

then ABC=117 cause its a bigger angle. It is more than 90 and less than 180

the other three are way too big to compare it to the angle is providing (ABC).

hope i helped a little

You might be interested in

Assume the random variable x is normally distributed with mean u = 86 and standard deviation o = 5. Find the indicated probabili

Vanyuwa [196]

Answer:

Step-by-step explanation:

6 0

3 years ago

List the first five multiples of 7?

Maurinko [17]

The first 5 factors of 7 are 7,14,21,28,35

3 0

4 years ago

Layla makes necklaces to sell online. she spends $46 on supplies at the first store and then $30 at the second store. she press

slava [35]

I believe the answer would be $57

7 0

3 years ago

To the nearest degree, what is m_A? Explain

noname [10]

Answer:

$A= 53$

Step-by-step explanation:

Given

$BC = 9,6$

$AC = 7.2$

Required: Angle A

This is calculated using:

$tan\ A = \frac{Opposite}{Hypotenuse}$

From the attachment;

$Opposite = 9.6$

$Adjacent = 7.2$

So:

$tan A =\frac{9.6}{7.2}$

$tan A =1.333$

Take arctan of both sides

$A= tan^{-1}(1.333$

$A= 53$ ----- approximated

7 0

3 years ago

Solve this system of linear inequalities ( will give brainiest)

lakkis [162]

From the graphs you can see that the graph of the line $y= \frac{1}{3} x-3$ lies under the graph of the line $y= \frac{1}{3} x-1$ . Then all solutions of unequality $y\le \frac{1}{3} x-3$ are solutions of unequality $y\le \frac{1}{3} x-1$ , but not all solutions of unequality $y\le \frac{1}{3} x-1$ are solutions of unequality $y\le \frac{1}{3} x-3$ .
For example, if x=1, y=-2
$-2\le \frac{1}{3} \cdot 1-1 =- \frac{2}{3} \\ -2\ \textgreater \ \frac{1}{3} \cdot 1-3=- \frac{8}{3}$ .
Answer: Correct choice is B.

3 0

4 years ago