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REY [17]
3 years ago
5

In the diagram below AE = 6, EB = 3, and DE = 2. Find CE

Mathematics
1 answer:
cluponka [151]3 years ago
4 0

Theorem: If two chords intersect within a circle, then the product of the lengths of the segments (parts) of one chord is equal to the product of the lengths of the segments of the other chord.

In your case,

AE\cdot EB=CE\cdot ED.

If AE = 6, EB = 3, and DE = 2, then

6\cdot 3=CE\cdot 2,\\ \\CE=\dfrac{6\cdot 3}{2}=9.

Answer: correct choice is D.

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Step-by-step explanation:

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Solve the system of equations using elimination.<br><br> 4x - 7y = 5<br> 9x – 7y = –15
Anni [7]

Step-by-step explanation:

We have to get one positive 7y so,

4x-7y=5

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multiply anyone of the equation by -1. I choose the first one so,

4x+7y=-5

9x-7y=-15

we can now cancel the y's so the equation will be left with

-4x=-5

9x=-15

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5x=-20

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x=-4

now plug in the x value in any one of the

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I choose the first one so,

4(-4)-7y=5

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8 0
4 years ago
West high schools population is 250 students fewer then twice the population of East High school the two schools have a total of
gizmo_the_mogwai [7]

Answer:

1036 students

Step-by-step explanation:

Let the number of students at West High be "w" and the number of students at East High be "e"

West High population is 250 FEWER than TWICE of East High, we can write:

w = 2e - 250

Total students in both schools is 2858, so we can write 2nd equation as:

e + w = 2858

We can replace 1st equation in 2nd to get an equation in e, and find "e":

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3 0
3 years ago
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Svetradugi [14.3K]

Answer:

Let p be the number of pencils.

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4p=12, p=3.

So Peter ends up with 33 and Tony with 11. 3*11=33, so that confirms that Tony gave Peter 3 pencils.

3 0
3 years ago
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