Pythagoras Theorem:
Apply Pythagoras Theorem:
a² + 6² = 11²
a² = 11² - 6²
a²= 85
a = √85
a = 9.22 (nearest hundredth)
Answer: RT = 9.22 cm
The equation is y= -2.
How? If you recall, a linear equation is y= mx+b. The m is the slope (growth) and b is the y-intercept ( where the line crosses the y-axis).
Now since there is no slope or m, the equation would look like this:
y= b or y= 0+b
Next, you want to input the coordinator points (0, -2) into the equation. reminder: (x, y) = x=0 y= -2
y= 0+ -2
y= -2
And there you go! The equation is y= -2. I hope I help you in solving this problem, if not message me, because I'll be glad to help you.
To determine whether 10a-10c are true or false, you first need to know how to find the volume of the shoebox and the volume of the crate.
The equation for volume is l × w × h where l is the length, w is the width, and h is the height.
So, the volume of the shoebox is
V = l × w × h
V = 12 × 6 × 4
V = 288 cubic inches.
To find the volume of the crate, we simply multiply the volume of one shoebox by 20, as the crate holds 20 shoeboxes.
228 × 20 = 4560 cubic inches.
10a. Each shoebox has a volume of 22 cubic inches. <span>False. The volume is 228 cubic inches.
</span>10b. Each crate has a volume of about 440 cubic inches. <span>False. The volume of each crate is 4560 cubic inches.</span><span>
</span>10c. If the crate could hold 27 shoeboxes, the volume of the crate would be about 7,776 cubic inches.
For this one, let's do some more math. Since we figured out the volume of a crate holding 20 shoeboxes is 4560 cubic inches, let's do the same thing to find the volume of a crate holding 27 shoeboxes.
228 × 27 = 6156 cubic inches.
<span>False. The volume of a crate holding 27 shoeboxes would be 6156 cubic inches.
</span>11 part A:
Each term above describes the term below, but the term below doesn't necessarily describe the term above.
The choice of terms is : <span>trapezoid</span>, <span>triangle</span>, <span>rhombus</span>, <span>parallelogram</span>
Before we do anything else, let's define our terms, as well as the ones used in the diagram.
Trapezoid - A four sided shape with a pair opposite parallel sides.<span>
Triangle - </span>A shape with three sides.<span>
Rhombus - </span>A shape with four equal straight sides<span>.
Parallelogram - </span>A quadrilateral with two sets of parallel sides.<span>
Quadrilateral - </span>A four-sided shape with four angles.<span>
Square - </span>A four-sided shape with all four sides the same length, and all four angles are the same size.
The first term is quadrilateral. From this, we can determine that the term <span>triangle</span> won't be used at all, as it's a three-sided figure, whereas a <span>quadrilateral</span> is a four-sided figure. This leaves <span>trapezoid, rhombus, </span>and <span>parallelogram </span>as our terms.
A <span>trapezoid </span>is a <span>quadrilateral</span>, because it has four sides, but it can't be a <span>rhombus </span>or <span>parallelogram</span>, so it goes in the first open box.
A parallelogram is a trapezoid, because it has a pair of opposite parallel sides, but it can't be a rhombus, because it doesn't necessarily have all equal sides, so it goes in the second open box.
A rhombus is a parallelogram, because it has two sets of parallel sides, and goes in the third open box.
So, from top box to bottom box, the order the term go is
Quadrilateral
Trapezoid
Parallelogram
Rhombus
Square
Answer:
B. 4 and 6 in
Step-by-step explanation:
The triangle inequality rule states: the length of a side of a triangle is less than the sum of the lengths of the other two sides and greater than the difference of the lengths of the other two sides.
So for the first qualification, we can eliminate A, C, and D. Therefore the answer is B, 4 & 6 in
, recall that ![\mathbb E[X]=\mu_X=np](https://tex.z-dn.net/?f=%5Cmathbb%20%0AE%5BX%5D%3D%5Cmu_X%3Dnp)
and ![\mathbb V[X]={\sigma_X}^2=np(1-p)](https://tex.z-dn.net/?f=%5Cmathbb%20V%5BX%5D%3D%7B%5Csigma_X%7D%5E2%3Dnp%281-p%29)
. So
