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IRINA_888 [86]
4 years ago
14

Can someone please help me SIMPLIFY #30 and #31 ????

Mathematics
1 answer:
____ [38]4 years ago
6 0
Basically, you just have to distribute and then add. Let's do that:

30. 
x( \frac{3}{2}x-2)+6( \frac{5}{2}x- \frac{2}{3})
(\frac{3}{2}x^2-2x)+( \frac{15}{2}x -4)

Combine like terms (and this is your answer):
\frac{3}{2}x^2- \frac{11}{2}x - \frac{2}{3}

31. Same thing (except convert 1 and 1/5 to an improper fraction):
(\frac{6}{5})(x+ \frac{3}{2})- \frac{9}{10}
\frac{6}{5}x + \frac{9}{5} - \frac{9}{10}
\frac{6}{5}x +  \frac{9}{10}

Hope this helped!

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Is the relation shown in the table below a function? Explain.
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a company that manufactures bicycles has a fixed cost of $80,000. it costs $100 to produce each bicycle. the total cost for the
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C(x) = 80000 + 100x is the total cost as function of number of cycles produced

C(90) = 89000 and it costs $ 89000 to produce 90 bicycles

<em><u>Solution:</u></em>

Given that, company that manufactures bicycles has a fixed cost of $80,000

Fixed cost = $ 80,000

Let x be the number of cycles produced

Let C(x) be the total cost as function of number of cycles produced

It costs $100 to produce each bicycle

Variable cost = 100 x number of cycles produced

variable cost = 100x

The total cost for the company is the sum of its fixed cost and variable costs

total cost = fixed cost + variable cost

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Thus total cost as function of "x" is found

<em><u>Find and interpret C(90)</u></em>

Substitute x = 90 in C(x)

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