Can anyone tel me what y equals in standard form?

Mathematics

2 answers:

lana [24]3 years ago

6 0

That’s thee asnawer kindsir

ss7ja [257]3 years ago

3 0

Answer:

y = x^2 +6x +8

Step-by-step explanation:

The vertex is located at (-3, -1) and the graph rises 1 unit vertically for 1 unit away from the vertex. This means the scale factor is 1 and the vertex form equation can be written as ...

y = a(x -h)^2 +k . . . . . vertex form with scale factor a, vertex (h, k)

y = (x -(-3))^3 +(-1) . . . fill in the values we know

y = (x +3)^2 -1 . . . . . simplify signs

y = x^2 +6x +9 -1 . . . eliminate parentheses

y = x^2 +6x +8 . . . . . your equation in standard form

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Sue Anne owns a medium-sized business. The probability model below describes the number of employees that may call in sick on an

Masja [62]

Answer:

The mean is $\mu = 2.1$

Step-by-step explanation:

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4 0

3 years ago

Find the perimeter of the polygon. Round your answer to the nearest tenth.

lubasha [3.4K]

Answer:

Perimeter is 38.8 units and approximately 39 units

Step-by-step explanation:

Given: Graph

To find: perimeter of the polygon

Solution:

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

As per the graph,

point P is (-2,11)

point Q is (-4,6)

point R is (2,0)

point S is (1,7)

point T is (8,7)

$PQ=\sqrt{(-4+2)^2+(6-11)^2}=\sqrt{(-2)^2+(-5)^2}=\sqrt{29}=5.4\,\,units\\QR=\sqrt{(2+4)^2+(0-6)^2}=\sqrt{(6)^2+(-6)^2}=\sqrt{72}=8.5\,\,units\\RS=\sqrt{(1-2)^2+(7-0)^2}=\sqrt{(-1)^2+(7)^2}=\sqrt{50}=7.1\,\,units\\ST=\sqrt{(8-1)^2+(7-7)^2}=\sqrt{(7)^2+(0)^2}=\sqrt{49}=7\,\,units\\PT=\sqrt{(8+2)^2+(7-11)^2}=\sqrt{(10)^2+(-4)^2}=\sqrt{116}=10.8\,\,units$