Answer:
<h2>The distance from the pitcher's mound and to second base is 37.99 approximately.</h2>
Step-by-step explanation:
The diamond is a square, which in this case has 50 feet long each side, and from home to pitcher is 38 feet. Notice that home is a vertex of the square and the pitcher's mound is the intersection of the diagonals, where they cut half.
We can find the distance from the pitcher to first base using Pythagorean's Theorem, where 50 feet is the hypothenuse.
Therefore, the distance from the pitcher to first base is 32.5 feet, approximately.
Now, we can use again Pythagorean's Theorem to find the distance from pitcher to second base, where the hypothenuse is 50 feet.
Therefore, the distance from the pitcher's mound and to second base is 37.99 approximately.
<em>(this results make sense, because the diagonals of a square intersect at half, that means all bases have the same distance from pitcher's mound, so the second way to find the distance asked in the question is just using theory)</em>
The exponential equations represents how long it will take for the account to grow to 1500 is y = 1000(b)^13.72
<h3>Exponential equations</h3>
Exponential equations are inverse of logarithmic equation. The standard exponential equation is expressed as;
y = ab^x
where
a is the base
x is the exponent
b is the rate
If Jennifer has a savings account that earns interest at a rate of 3% per year. Jennifer deposits 1000 into the account, the resulting exponential equation will be:
y = 1000(1.03)^x
If y = 1500, find the value of x
1500 = 1000(1.03)^x
1.5 = 1.03^x
ln1.5 = xln1.03
x = ln1.5/ln1.03
x = 13.72
Substitute to determine the equation
y = 1000(b)^13.72
Hence the exponential equations represents how long it will take for the account to grow to 1500 is y = 1000(b)^13.72
Learn more on exponential equation here: brainly.com/question/2456547
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Answer:
x=0
y=-14
Step-by-step explanation:
If the equation is y=2x-14,
If x=0,
enter x into the equation
y=2(0)-14
y=0-14
y=-14
Answer:
TRUE
Step-by-step explanation:
Lateral area of cone is given by: πrl
where r is the radius and l is the slant height
Here r=r and l=2h
Hence, lateral area of cone A= π×r×2h
= 2πrh
Lateral area of cylinder is given by: 2πrh
where r is the radius and h is the height
Lateral area of cylinder B=2πrh
Clearly, both the lateral areas are equal
Hence, the statement that:The lateral surface area of cone A is equal to the lateral surface area of cylinder B. is:
True
