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3 years ago

14

I HAVE 5 MINS ANSWER THIS FOR (15 POINTS)

2 answers:

slamgirl [31]3 years ago

3 0

Answer:

d

Step-by-step explanation:

vladimir1956 [14]3 years ago

3 0

Answer:

Domain: 0,2,3

Range: -1,-3,-2

Step-by-step explanation:

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$10,000 at an annual rate of 7%, compounded semi-annually, for 2 years

forsale [732]

Answer:

$\$13,107.96$

Step-by-step explanation:

Since interest is compounded semi-annually (half a year or 6 months), in a spawn of 2 years, the interest will have been compounded 4 times. As given in the problem, each time the interest is compounded, the new balance will be 107% or 1.07 times the amount of the old balance.

Therefore, we can set up the following equation to find the new balance after 2 years:

$\text{New balanace}=10,000\text{ (old balance)}\cdot 1.07\cdot 1.07\cdot 1.07\cdot 1.07,\\\text{New balanace}=10,000\cdot 1.07^4=\boxed{\$13,107.96}$

8 0

3 years ago

Which is the MOST precise measurement this ruler can give for the green strip of paper? A) 4.00 inches B) 4.25 inches C) 4.50 in

Alenkinab [10]

The most precise is 4.00 because that is equal to 10.16 cm and that is the most closes to an exact measurment.

3 0

3 years ago

the audience in a theatre is made up of the following ratio: men:women:children 3:4:5. there are 348 people in the audience. cal

scoundrel [369]

There are 87 men 3 is the male ratio You add all the ratios 3+4+5=12 3/12×348 =87

7 0

3 years ago

The radius of a sphere is increasing at a rate of 2 mm/s. How fast is the volume increasing (in mm3/s) when the diameter is 40 m

daser333 [38]

Answer:

$\dfrac{dV}{dt}=502.65\ mm^3/s$

Step-by-step explanation:

The volume of a sphere is given by :

$V=\dfrac{4}{3}\pi r^3$

The rate of change of volume means,

$\dfrac{dV}{dt}=\dfrac{d}{dt}(\dfrac{4}{3}\pi r^3)\\\\\dfrac{dV}{dt}=\dfrac{4}{3}\pi \times 3r\times \dfrac{dr}{dt}$

We have, $\dfrac{dr}{dt}=2\ mm/s\ and\ r=40\ mm$

So,

$\dfrac{dV}{dt}=\dfrac{4}{3}\pi \times 3\times 20\times 2\\\\=502.65\ mm^3/s$

So, the volume is increasing at the rate of $502.65\ mm^3/s$ .

6 0

3 years ago

Which is closest to the surface area of the figure?

storchak [24]

A I think I’m sorry if I’m wrong haven’t done this in a while

8 0

2 years ago