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valkas [14]
3 years ago
14

2) Puppy B weighs 8 pounds, which is about 75% of its adult weight. What will be the

Mathematics
2 answers:
masha68 [24]3 years ago
6 0

Answer:

Puppy A weighs 8 pounds, which is about 25% of its adult weight. What will be the adult weight of Puppy A? Puppy B weighs 8 pounds, which is about 75% of its adult weight. What will be the adult weight of Puppy B?

Step-by-step explanation:

jekas [21]3 years ago
3 0
I agree with the person above
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0.42 - 4) = 0.24 + 7)
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Answer:

im sorry if not but i think its 7.24

Step-by-step explanation:

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Mindy is purchasing songs from an album on
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Answer:3003

Step-by-step explanation:

14 choose 6 is 3003 because 14!/6!(14-6)!=9*10*11*12*13*14/6!=3003

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3 years ago
Plz help ASAP 8(5 – n) = 2n
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Answer:

n=4

Step-by-step explanation:

Distribute the 8. and then subtract 8n from both sides and divide 40 and 10n.

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What is the sum of the angle measures in a 22-gon?<br><br> 360°<br> 2,200°<br> 3,600°<br> 3,960°
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Exhibit 9-2 The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the cu
Diano4ka-milaya [45]

Answer:

At a .05 level of significance, it can be concluded that the mean of the population is significantly more than 3 minutes.

Step-by-step explanation:

We want to test to determine whether or not the mean waiting time of all customers is significantly more than 3 minutes.

At the null hypothesis, we test if the mean is of at most 3 minutes, that is:

H_0: \mu \leq 3

At the alternative hypothesis, we test if the mean is of more than 3 minutes, that is:

H_1: \mu > 3

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

3 is tested at the null hypothesis:

This means that \mu = 3

The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in the sample to check out was 3.1 minutes. The population standard deviation is known to be 0.5 minute.

This means that n = 100, X = 3.1, \sigma = 0.5

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{3.1 - 3}{\frac{0.5}{\sqrt{100}}}

z = 2

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 3.1, which is 1 subtracted by the p-value of z = 2.

Looking at the z-table, z = 2 has a p-value of 0.9772.

1 - 0.9772 = 0.0228

The p-value of the test is of 0.0228 < 0.05, meaning that the is significant evidence to conclude that the mean of the population is significantly more than 3 minutes.

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