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valkas [14]
3 years ago
14

2) Puppy B weighs 8 pounds, which is about 75% of its adult weight. What will be the

Mathematics
2 answers:
masha68 [24]3 years ago
6 0

Answer:

Puppy A weighs 8 pounds, which is about 25% of its adult weight. What will be the adult weight of Puppy A? Puppy B weighs 8 pounds, which is about 75% of its adult weight. What will be the adult weight of Puppy B?

Step-by-step explanation:

jekas [21]3 years ago
3 0
I agree with the person above
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Triss [41]

Answer:

2+3s

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Write down a pair of integers whose
liubo4ka [24]
<span>The pair of integers that I chose are:

(a) sum is –3
5 + (-8) = -3

(b) difference is –5
2 - 7 = -5

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3 0
3 years ago
Please help me w this an explain how you got it!.
pishuonlain [190]

Answer:

Vertex → (2, 4)

Step-by-step explanation:

Quadratic equation has been given as,

y = -x² + 4x

We rewrite this equation in the form of a function as,

f(x) = - x² + 4x

By comparing this equation with the standard quadratic equation,

y = ax² + bx + c

a = -1 and b = 4

Vertex of the parabola represented by this equation is given by [-\frac{b}{2a}, f(\frac{-b}{2a})]

x coordinate = -\frac{4}{2(-1)}

                     = 2

y-coordinate = f(2)

                     = - (2)² + 4(2)

                     = -4 + 8

                     = 4

Therefore, vertex of the given function is (2, 4)

6 0
2 years ago
Find 10 partial sums of the series. (round your answers to five decimal places.) ∞ 15 (−4)n n = 1
nikklg [1K]
Given

\Sigma_{n=1}^\infty15(-4)^n

The first 10 partial sums are as follows:

S_1=\Sigma_{n=1}^{1}15(-4)^n=15(-4)=\bold{-60} \\  \\ S_2=\Sigma_{n=1}^{2}15(-4)^n=\Sigma_{n=1}^{1}15(-4)^n+15(-4)^2 \\ =-60+15(16)=-60+240=\bold{180} \\  \\ S_3=\Sigma_{n=1}^{3}15(-4)^n=\Sigma_{n=1}^{2}15(-4)^n+15(-4)^3 \\ =180+15(-64)=180-960=\bold{-780} \\  \\ S_4=\Sigma_{n=1}^{4}15(-4)^n=\Sigma_{n=1}^{3}15(-4)^n+15(-4)^4 \\ =-780+15(256)=-780+3,840=\bold{3,060} \\  \\ S_5=\Sigma_{n=1}^{5}15(-4)^n=\Sigma_{n=1}^{4}15(-4)^n+15(-4)^5 \\ =3,060+15(-1,024)=3,060-15,360=\bold{-12,300}

S_6=\Sigma_{n=1}^{6}15(-4)^n=\Sigma_{n=1}^{5}15(-4)^n+15(-4)^6 \\ =-12,300+15(4,096)=-12,300+61,440=\bold{49,140}

The rest of the partial sums can be obtained in similar way.
7 0
3 years ago
The maximum number of students in a classrom is 26 if there are 16 signed up for the art class
Aleks04 [339]

Answer:whats the question

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