A group of related facts that use the same numbers is an

Find the product and express your answer in scientific notation. (1.3 x 10-6)(4 x 1010)

sveticcg [70]

$(1.3\cdot10^{-6})(4\cdot10^{10})=(1.3\cdot4)(10^{-6}\cdot10^{10})=5.2\cdot10^{-6+10}\\\\=\boxed{5.2\cdot10^4}$

3 0

3 years ago

If you have an avocado and then you get 10 and then you get6 coconut and then you get 20 sandwiches what is it equal

icang [17]

Answer:

36

Step-by-step explanation:

you just add all of the numbers together

5 0

3 years ago

Assume the random variable x is normally distributed with mean μ = 80 and standard deviation σ = 4. Find the indicated probabili

Schach [20]

Answer:

0.2278

Step-by-step explanation:

z = (x-μ)/σ,

where x is the raw score

μ is the population mean

σ is the population standard deviation

z => 72 - 80/4

= -2

Probability value from Z-Table:

P(x ≤ 72) = P(x = 72) => P(x < 72)

0.02275

Approximately =>0.2278

6 0

3 years ago

If vector u has its initial point at (-7, 3) and its terminal point at (5, -6), u =

attashe74 [19]

First of all, let θθ be some angle in (0,π)(0,π). Then

θθ is acute ⟺⟺ θ<π2θ<π2 ⟺⟺ cosθ>0cos⁡θ>0.θθ is right ⟺⟺ θ=π2θ=π2 ⟺⟺ cosθ=0cos⁡θ=0.θθ is obtuse ⟺⟺ θ>π2θ>π2 ⟺⟺ cosθ<0cos⁡θ<0.

Now, to see if (say) angle AA of the triangle ABCABC is acute/right/obtuse, we need to check whether cos∠BACcos⁡∠BAC is positive/zero/negative. But what is cos∠BACcos⁡∠BAC? It is the angle made by the vectors AB−→−AB→ and AC−→−AC→. (When you are computing the angle at a particular vertex vv, you should make sure that both the vectors corresponding to the two adjacent sides have that vertex vv as the initial point.) We will first compute these two vectors:

AB−→−=(0,0,0)−(1,2,0)=(−1,−2,0)AB→=(0,0,0)−(1,2,0)=(−1,−2,0)AC−→−=(−2,1,0)−(1,2,0)=(−3,−1,0)AC→=(−2,1,0)−(1,2,0)=(−3,−1,0)Therefore, the angle between these vectors is given by:cos∠BAC=AB−→−⋅AC−→−|AB−→−||AC−→−|=…(1)(1)cos⁡∠BAC=AB→⋅AC→|AB→||AC→|=…Can you take it from here? From the sign of this value, you should be able to decide if angle AA is acute/right/obtuse.

Now, do the same procedure for the remaining two angles BB and CC as well. That should help you solve the problem.

A shortcut. Since you are not interested in the actual values of the angles, but you need only whether they are acute, obtuse or right, it is enough to compute only the sign of the numerator (the dot product between the vectors) in formula (1). The denominator is always positive.

6 0

3 years ago

Graph the function r(x) = x + 5

Gwar [14]

Slope:

$1$

y-intercept:

(0,5)

HopeItHelps you

7 0

3 years ago