What is three and one third divided by two aand one third?

A recent survey by the American Cancer Society shows that the probability that someone is a smoker is P(S) = 0.19. It has also d

nekit [7.7K]

0.19*0.158=0.03002 -------> 0.03

8 0

3 years ago

I'm stuck on this please help!!

kvv77 [185]

The answer is D
$\frac{12 {x}^{6} {y}^{ - 4} {z}^{2} }{3 {x}^{2} {y}^{ - 6} {z}^{3} } \\ = \frac{4 {x}^{4} {y}^{2} }{z}$

5 0

4 years ago

Kimane and a friend picked apples. Kimane picked 4 2/3 and his friend picked 5 5/6 pounds. About how many pound of apples do the

Gala2k [10]

Answer:

$9\dfrac{1}{2}$

Step-by-step explanation:

To find many more pounds of apples Kimane and his friend needs to get, we first need to find out how many pounds of apples they picked together.

Kimane = $4\dfrac{2}{3}$

Friend = $5\dfrac{5}{6}$

We add them together to find out how many pounds of apples they currently have.

Total Pounds = $4\dfrac{2}{3}+5\dfrac{5}{6}$

Just to make the equation clearer, we separate the whole numbers from the fractions.

$=4+5+\dfrac{2}{3}+\dfrac{5}{6}$

$=9+\dfrac{2}{3}+\dfrac{5}{6}$

Now since we cannot add the 2 fractions directly since they have different denominators, we need to convert the $/dfrac{2}{3}$ into a fraction with the same denominator.

We multiply both the numerator and denominator by 2 to have the same denominator.

$\dfrac{2*2}{3*2}=\dfrac{4}{6}$

So now we have:

$=9+\dfrac{4}{6}+\dfrac{5}{6}$

$=9+\dfrac{9}{6}or1\dfrac{1}{2}$

$Total Pounds = 10\dfrac{1}{2}$

Now that we know how many pounds Kimane and his friend collected, we simply subtract 20 and the total amount Kimane and his friend had already collected.

$20-10\dfrac{1}{2}$

$=9\dfrac{1}{2}$

So Kimane and his friend still need to get $9\dfrac{1}{2}$ more pounds of apples to get 20 pounds of apples.

6 0

3 years ago

Kyla makes a triangular school pennant. The area of the triangle is 180 square inches. The base of the pennant is z inches long.

HACTEHA [7]

I took the test, the answer is C, 30.

5 0

3 years ago

Read 2 more answers

Given two angles that measure 50 degrees and 80 degrees and side that measures 4 feet, how many triangles, if any, can be constr

kirza4 [7]

The angles are the only constraint here that counts. If one of the three interior angles of a supposed triangle is 50 degrees and another is 80 degrees, then the third angle must be 50 degrees. Thus, we have a 50-50-80 triangle, which is isosceles though not a right triangle. If 4 feet is a measure of one of the equal sides of a supposed triangle, then obviously the adjacent side also has measure 4 ft.

The set of angles remains the same (50-50-80), but subject to the constraint mentioned above, the measure of any one of the sides has infinitely many possible values, so long as those values are positive.

3 0

3 years ago