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Alexus [3.1K]
3 years ago
14

You draw two cards from a standard deck of 52 cards. What is the probability of drawing a queen and then a king consecutively fr

om the deck without replacement?
Mathematics
2 answers:
Orlov [11]3 years ago
8 0

Answer: D

Step-by-step explanation:

Gelneren [198K]3 years ago
3 0

Answer:

4/663

Step-by-step explanation:

There are 4 queens and 4 kings in a deck. Drawing a queen would be 4/52. Drawing a king afterwards with replacing the queen would be 4/51 because you took a queen but didn't replace that one queen card so the deck has only 51 cards left after you drew the queen. Drawing a queen would not affect your chance of drawing a king card, it will only affect the total number of cards left because you didn't replace the card afterwards. 4*4=16;52*51=2652. 16/2652 can be simplified to 4/663 by dividing 4 to both numbers. 16/4=4 and 2652/4=663. The probability of drawing a queen then a king without replacement would be 4/663.

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1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n
Andrew [12]
Part 1
We are given x^2-21x=-4x. This can be rewritten as x^2-18x=0.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
     x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}
     x=\frac{18\pm 18}{2}

The values of x are
     x_1=\frac{18-18}{2}=0
     x_2=\frac{18+18}{2}=18

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function. 

Part 3.
The first equation is y=x^2+2.
The second equation is y=3x+20.

We have 
     x^2+2=3x+20
     x^2-3x-18=0
Factoring, we have 
     \left(x-6\right)\left(x+3\right)=0
Equating both factors to zero.
     x_1-6=0\rightarrow x_1=6
     x_2+3=0\rightarrow x_2=-3

When the value of x is 6, the value of y is 
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When the value of x is -3, the value of y is 
     y=3\left(-3\right)+20=11

Therefore, the solutions are (6,38) or (-3,11)
7 0
2 years ago
How can you tell if a number is divided by 4
Elan Coil [88]
If the last two digits of the number are divisible by four
4 0
3 years ago
Read 2 more answers
A red balloon starts at 7.3 meters off the ground and rises at 2.6 meters per second. A blue balloon starts at 12.4 meters off t
nexus9112 [7]
This problem is an example of solving equations with variables on both sides. To solve, we must first set up an equation for both the red balloon and the blue balloon. 

Since the red balloon rises at 2.6 meters per second, we can represent this part of the equation as 2.6s. The balloon is already 7.3 meters off of the ground, so we just add the 7.3 to the 2.6s: 

2.6s + 7.3

Since the blue balloon rises at 1.5 meters per second, we can represent this part of the equation as 1.5s. The balloon is already 12.4 meters off of the ground, so we just add the 12.4 to the 1.5:

1.5s + 12.4

To determine when both balloons are at the same height, we set the two equations equal to each other: 

2.6s + 7.3 = 1.5s + 12.4

Then, we solve for s. First, the variables must be on the same side of the equation. We can do this by subtracting 1.5s from both sides of the equation: 

1.1s + 7.3 = 12.4

Next, we must get s by itself. We work towards this by subtracting 7.3 from both sides of the equation: 

1.1s = 5.1

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This means that it will take 4.63 seconds for both balloons to reach the same height. If we want to know what height that is, we simply plug the 4.63 back into each equation: 

2.6s + 7.3
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1.5s + 12.4
= 1.5 (4.63) + 12.4
= 19.33

After 4.63 seconds, the balloons will have reached the same height: 19.33 meters.
6 0
3 years ago
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kobusy [5.1K]
The first thing we must do for this case is to define variables.
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 Answer:
 
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3 0
3 years ago
Additive inverse of 2/8​
balu736 [363]

Answer:

-2/8is it's answer

Step-by-step explanation:

mark as Brainlist

6 0
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