Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
Answer:
.4=a
Step-by-step explanation:
self explanatory
Answer:
1.8
Step-by-step explanation:
Solve for x
90
x
=
81
+
25
x
2
Subtract
25
x
2
from both sides of the equation.
90
x
−
25
x
2
=
81
Subtract
81
from both sides of the equation.
90
x
−
25
x
2
−
81
=
0
Factor the left side of the equation.
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−
(
5
x
−
9
)
2
=
0
Multiply each term in
−
(
5
x
−
9
)
2
=
0
by
−
1
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(
5
x
−
9
)
2
=
0
Set the
5
x
−
9
equal to
0
.
5
x
−
9
=
0
Solve for
x
.
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x
=
9
5
The result can be shown in multiple forms.
Exact Form:
x
=
9
5
Decimal Form:
x
=
1.8
Mixed Number Form:
x
=
1
4
5
Upgrade to
Answer:17,000
Step-by-step explanation:Add 532+150=680 then times it by 25 which equals 17,000
I = PRT
P = 8000
T = 4
R = 12%...turn to decimal...0.12
now we sub
I = (8000)(0.12)(4)
I = 3840 <==