Answer:
// program in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// string array
string m[3];
// array to store rainfall
double rainfall[3];
// variables
double avg_rainfall,sum=0;
for(int i=0;i<3;i++)
{
cout<<"Enter name of month "<<i+1<<" :";
// read month name
cin>>m[i];
cout<<"Enter rainfall (inches) in month "<<i+1<<" :";
// read rainfall
cin>>rainfall[i];
// sum of rainfall
sum+=rainfall[i];
}
// Average rainfall
avg_rainfall=sum/3;
// print Average rainfall
cout<<"Average rainfall for "<<m[0]<<","<<m[1]<<","<<m[2]<<" is "<<avg_rainfall<<" inches."<<endl;
return 0;
}
Explanation:
Create string array "m" to store name of month and double array "rainfall" to store rainfall. Read name of 3 months and rainfall in that month.Find the sum of all the rainfall and the average rainfall.Print the average rainfall of 3 months.
Output:
Enter rainfall (inches) in month 2 :45
Enter name of month 3 :july
Enter rainfall (inches) in month 3 :43
Average rainfall for may,june,july is 42.6667 inches.
Answer:
TRUE, The PC is always incremented by the same amount in fixed-length instruction set architectures.
Explanation:
Its TRUE that Program Counter ( PC ) is always incremented by the same amount in fixed - length instruction set architectures ( fixed length ISA) . As the instruction set length is fixed in fixed - length instruction set architectures, the Program Counter to fetch the next instruction set it has to be incremented by fixed length. This fixed length depends on the hardware of the architecture (the number of bytes each machine word contains and number of machine words per memory location)
