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3 years ago

-x-6y=10 x-2y=-2 using elimination?

Mathematics

2 answers:

Lana71 [14]3 years ago

4 0

Answer: x = -4, y = 1

AleksAgata [21]3 years ago

3 0

If we add the two equations we get:
-x - 6y + x - 2y = 10 + (-2)
-8y = 8, therefor y = -1

If y = -1:
-x - 6(-1) = 10
-x + 6 = 10
-x = 4
x = -4

Therefor the solution would be (-4, -1)

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egoroff_w [7]

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3 years ago

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boyakko [2]

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$\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\a_1=2000\\r=1.1\\n=4\end{cases}\\\\\\S_4=2000\left[ \cfrac{1-(1.1)^4}{1-1.1} \right]\implies S_4=2000\left(\cfrac{-0.4641}{-0.1} \right)\\\\\\S_4=2000(4.641)\implies S_4=9282$

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3 years ago

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Delicious77 [7]

Answer:

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3 years ago