Explanation:The initial number of horses = 24
year = 2011
Coordinates (2011, 24)
when the number of horses became 32, year was 2014
Coordinates (2014, 32)
We find the slope = rate of change
slope = change in number of horses/change in number of years
slope = (32-24)/(2014-2011)
slope = 8/3
The point slope formula:
The number of horses in year 2020
using points: (2011, 24) and (2020, y), we equate with the slope since it is constant for any two points on this model.
8/3 = (y - 24)/(2020 - 2011)
8/3 = (y - 24)/9
cross multiply:
8(9) = 3(y - 24)
72 = 3y - 72
72 + 72 = 3y
144 = 3y
144/3 = 3y/3
y = 48
Hence, there will be 48horses in 2020 (option A)
1. Replace f(x) with y: y = 3x - 15
2. Interchange x and y: x = 3y - 15
3. Solve this for y: 3y = x + 15, and y = (x + 15)/3
4. Replace y with
-1 -1
f (x): f (x) = (x + 15) / 3 (answer)
Answer:
Step-by-step explanation:
1. A car requires 22 litres of petrol to travel a distance of 259.6 km
what is the distance that the car can travel on 63 ltr of petrol
22ltr = 259.6km
63ltr=
cross multiply
{63 x 259.6}/22 = 16354.8/22 = 743.4 km
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km
2. To travel a distance of 2013.2 km
we would need to calculate the amount of fuel
A car requires 22 litres of petrol to travel a distance of 259.6 km
what amount of fuel would it require to travel 2013.2km
22ltr = 259.6km
xltr = 2013.2km
x is the value of petrol to cover 2013.2km
cross multiply
(2013.2 x 22)/259.6
44290.4/259.6 = 170.610169492≈170.6 ltr
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km
if 1ltr is $1.99
170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5
The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5
Area for square = s² = 196x¹²y¹⁰z⁶
s = √(<span>196x¹²y¹⁰z⁶)
s = 14x</span>⁶y⁵z³
Perimeter = 4*s = 4*(14x⁶y⁵z³) = 56x<span>⁶y⁵z³
Perimeter = 56</span>x<span>⁶y⁵z³ D</span>
