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4 years ago

22. Francisco is three years more than twice Jenna's age. Harrison is two years less than three times Jenna's age.

Mathematics

1 answer:

Jet001 [13]4 years ago

6 0

Answer:

An expression for Francisco's age in terms of a is (2a+3)

An expression for Harrison's age in terms of a is (3a-2)

An expression for the sum of all three ages, in terms of a is (6a+1)

Step-by-step explanation:

Let

a -----> Jenna's age

b -----> Francisco's age

c -----> Harrison's age

we know that

Francisco's age is two times Jenna's age plus three years

b=2a+3 -----> equation A

Harrison's age is three times Jenna's age minus two years

c=3a-2 ----> equation B

The sum of all three ages, in terms of a is

(a+b+c) -----> equation C

substitute equation A and equation B in equation C

a+(2a+3)+(3a-2)

Combine like terms

(a+2a+3a)+(3-2)

6a+1

therefore

An expression for Francisco's age in terms of a is (2a+3)

An expression for Harrison's age in terms of a is (3a-2)

An expression for the sum of all three ages, in terms of a is (6a+1)

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