Answer:
The correct answer would be C. 0.60
It can be calculated with the help of Hardy-Weinberg equation i.e
p² + q² + 2pq = 1
Also, p + q = 1
- where p represents the frequency of dominant allele.
- q represents the frequency of recessive allele.
- p² represents the frequency of homozygous dominant genotype
.
- q² represents the frequency of homozygous recessive genotype
.
- 2pq represents the frequency of heterozygous genotype.
Number of homozygous dominant (YY) = 36
Number of homozygous recessive (yy) = 16
Number of heterozygous dominant (Yy) = 48
Total number of plants = 100
Now, frequency of homozygous dominant (YY) = 36/100 = 0.36
Therefore, p² = 0.36
So, p = √0.36 = 0.60
Hence, frequency of dominant allele (Y) = 0.60
Answer:
A, Checks and balances and separation of powers.
Explanation:
The nucleus contains the protons and neutrons giving it the most mass
I believe it is a secondary consumer
