Question

If the quadratic formula is used to solve 2x2 = 8x -3, what are the solutions

Answer 1

Answer:

x = 2 ± $\frac{1}{2}$$\sqrt{10}$

Step-by-step explanation:

Given a quadratic equation in standard form : ax² + bx + c = 0

Then we can solve for x using the quadratic formula

Given

2x² = 8x - 3 ( subtract 8x - 3 from both sides )

2x² - 8x + 3 = 0 ← in standard form

with a = 2, b = - 8 and c = 3, hence

x = (- (- 8) ± $\sqrt{(-8)^2-(4(2)(3)}$) / 4

  = (8 ± $\sqrt{64-24}$) / 4

  = (8 ± $\sqrt{40}$) / 4

  = (8 ± 2$\sqrt{10}$ ) / 4

  = $\frac{8}{4}$ ± $\frac{2\sqrt{10} }{4}$

  = 2 ± $\frac{1}{2}$$\sqrt{10}$

 

Answer 2

Answer:

2x2 = 8x-3

4 = 8x - 3 | +3

7=8x

x=7/8

Step-by-step explanation: