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zvonat [6]
3 years ago
13

If the quadratic formula is used to solve 2x2 = 8x -3, what are the solutions

Mathematics
2 answers:
Nataly_w [17]3 years ago
7 0

Answer:

x = 2 ± \frac{1}{2}\sqrt{10}

Step-by-step explanation:

Given a quadratic equation in standard form : ax² + bx + c = 0

Then we can solve for x using the quadratic formula

Given

2x² = 8x - 3 ( subtract 8x - 3 from both sides )

2x² - 8x + 3 = 0 ← in standard form

with a = 2, b = - 8 and c = 3, hence

x = (- (- 8) ± \sqrt{(-8)^2-(4(2)(3)}) / 4

  = (8 ± \sqrt{64-24}) / 4

  = (8 ± \sqrt{40}) / 4

  = (8 ± 2\sqrt{10} ) / 4

  = \frac{8}{4} ± \frac{2\sqrt{10} }{4}

  = 2 ± \frac{1}{2}\sqrt{10}

 

seraphim [82]3 years ago
3 0

Answer:

2x2 = 8x-3

4 = 8x - 3 | +3

7=8x

x=7/8

Step-by-step explanation:

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Solve for the indicated variable in the literal equation ​
ANTONII [103]

Answer:

x = \frac{y}{3} - \frac{5}{3}

Step-by-step explanation:

Given

y = 5 + 3x

Required

Solve for x

Subtract 5 from both sides

y-5 = 5 -5+ 3x

y-5 = 3x

Divide through by 3

\frac{y}{3} - \frac{5}{3} = x

x = \frac{y}{3} - \frac{5}{3}

8 0
3 years ago
Given JM=27, ml=16, jl=46, nk=15, KLM= 48, JkM=78, MJL=22, find each missing value.
Llana [10]

Answer:

KL = 27

JK = 16

MK = 30

NL = 23

m∠JKL = 132°

m∠KLJ = 22°

m∠KMJ = 54°

m∠KJL = 26°

Step-by-step explanation:

The given parameters of the quadrilateral JKLM are;

JM = 27, ML = 16, JL = 46, NK = 15, KLM = 48, JKM = 78, MJL = 22

Taking the sides as parallel, we have that quadrilateral JKLM is a parallelogram

Therefore;

KL = JM = 27

JK = ML = 16

m∠KLJ = m∠MJL = 22°

MN = NK = 15

MK = MN + NK = 15 + 15 = 30

NL = JL/2 = 46/2 = 23

m∠KJM = m∠KLM = 48°

m∠KJL = m∠KLM - m∠MJL = 48° - 22° = 26°

m∠KML = m∠JKM = 78°

m∠MKL = 180° - m∠KML - m∠KLM = 180° - 78° - 48° = 54°

m∠MKL = 54°

m∠JKL = m∠JKM + m∠MKL = 78° + 54° = 132°

m∠KMJ = m∠MKL = 54°

3 0
2 years ago
Given the rational inequality below, explain why the solution set includes 3, but does not include 1? Make sure to write the fin
pychu [463]
Because there is no solution if any number divide by 0

3 0
3 years ago
Solving a trigonometric equation involving an angle multiplied by a constant
PIT_PIT [208]

In these questions, we need to follow the steps:

1 - solve for the trigonometric function

2 - Use the unit circle or a calculator to find which angles between 0 and 2π gives that results.

3 - Complete these angles with the complete round repetition, by adding

2k\pi,k\in\Z

4 - these solutions are equal to the part inside the trigonometric function, so equalize the part inside with the expression and solve for <em>x</em> to get the solutions.

1 - To solve, we just use algebraic operations:

\begin{gathered} \sqrt[]{3}\tan (3x)+1=0 \\ \sqrt[]{3}\tan (3x)=-1 \\ \tan (3x)=-\frac{1}{\sqrt[]{3}} \\ \tan (3x)=-\frac{\sqrt[]{3}}{3} \end{gathered}

2 - From the unit circle, we can see that we will have one solution from the 2nd quadrant and one from the 4th quadrant:

The value for the angle that give positive

+\frac{\sqrt[]{3}}{3}

is known to be 30°, which is the same as π/6, so by symmetry, we can see that the angles that have a tangent of

-\frac{\sqrt[]{3}}{3}

Are:

\begin{gathered} \theta_1=\pi-\frac{\pi}{6}=\frac{5\pi}{6} \\ \theta_2=2\pi-\frac{\pi}{6}=\frac{11\pi}{6} \end{gathered}

3 - to consider all the solutions, we need to consider the possibility of more turn around the unit circle, so:

\begin{gathered} \theta=\frac{5\pi}{6}+2k\pi,k\in\Z \\ or \\ \theta=\frac{11\pi}{6}+2k\pi,k\in\Z \end{gathered}

Since 5π/6 and 11π/6 are π radians apart, we can put them together into one expression:

\theta=\frac{5\pi}{6}+k\pi,k\in\Z

4 - Now, we need to solve for <em>x</em>, because these solutions are for all the interior of the tangent function, so:

\begin{gathered} 3x=\theta \\ 3x=\frac{5\pi}{6}+k\pi,k\in\Z \\ x=\frac{5\pi}{18}+\frac{k\pi}{3},k\in\Z \end{gathered}

So, the solutions are:

x=\frac{5\pi}{18}+\frac{k\pi}{3},k\in\Z

4 0
1 year ago
The dimensions of a rectangular prism are shown below: Length: 1 and 1 over 3 feet Width: 1 foot Height: 2 and 1 over 3feet The
Andreas93 [3]

9514 1404 393

Answer:

  • 84 small cubes
  • 3 1/9 unit cubes

Step-by-step explanation:

A cube that is 1/3 ft on a side will fit 3 in a foot. In terms of the 1/3 ft small cube, the dimensions of the prism are ...

  1 1/3 ft = 4 small cubes

  1 ft = 3 small cubes

  2 1/3 ft = 7 small cubes

Then the volume in terms of small cubes is ...

  V = LWH = (4)(3)(7) = 84 small cubes

__

There are 3×3×3 = 27 small cubes in a 1-ft unit cube, so the prism volume in terms of unit cubes is ...

  84/27 = 3 1/9 . . . unit cubes

__

<em>Additional comment</em>

The largest dimension of the prism is just over 2 ft, so the maximum number of unit (1 ft) cubes that will fit is 2. To fill the volume with 3 1/9 unit cubes, those would have to be cut and fit into the space.

8 0
3 years ago
Read 2 more answers
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