4 years ago

How to solve Q 8,9,and 10.

Mathematics

1 answer:

iVinArrow [24]4 years ago

8 0

Answer:

bbbbbbbbbbbbbbbbbbbbbbbbbb

Step-by-step explanation:

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Answer:

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3 years ago

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What is the value of x in the equation 1/5x – 2/3y = 30, when y = 15? 4 8 80 200

miv72 [106K]

Start with 1/5x – 2/3y = 30. Let y = 15: (1/5)x – (2/3)(15) = 30

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3 years ago

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just olya [345]

Answer:

$978

Step-by-step explanation:

Given:

y = amount of profit
x = selling price of each widget
$y=-x^2+78x-543$

To find the maximum amount of profit, differentiate the equation, set it to zero and solve for x. Substitute found value of x into the original equation.

Differentiate equation

$y=-x^2+78x-543$

$\implies \dfrac{dy}{dx}=-2x+78$

Set differentiated equation to zero and solve for x:

$\dfrac{dy}{dx}=0$

$\implies -2x+78=0$

$\implies 2x=78$

$\implies x=39$

Maximum profit

Substitute x = 39 into the equation:

$\implies -(39)^2+78(39)-543=978$

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3 years ago

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