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Alchen [17]
3 years ago
13

If a= 3 -1 5 and b= 5 3 1

Mathematics
1 answer:
tiny-mole [99]3 years ago
7 0

Answer:

det(A)=-det(B)

Step-by-step explanation:

We have two matrices A, and B.

Matrix B is obtained by swapping rows 1 and 3 of matrix A.

Whenever we swap rows in matrices, the determinants does not change but the sign changes.

Therefore

det(A)=-det(B)

Also no two rows of of both matrices are the same, therefore

det(A)≠0, and det(B)≠0

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Jayden is downloading songs onto his MP3 player. One song is 5 minutes long,another is 2 minutes long,and a third is between the
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Answer:

<u><em>Jayden is downloading songs onto his MP3 player. One song is 5 minutes long,another is 2 minutes long,and a third is between the lengths of the other two songs. What is the total length of all three songs?</em></u>

<u><em>Step-by-step explanation:</em></u>

<u><em>Jayden is downloading songs onto his MP3 player. One song is 5 minutes long,another is 2 minutes long,and a third is between the lengths of the other two songs. What is the total length of all three songs? </em></u>

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3 years ago
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You missed an A in your art course by only 7 points. Your point total for the course was 371. How many points were possible in t
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The number of points that  were possible in the course is 420

What is the required number of points for grade A?

The number of points the student needs to have to make grade A is the student's current points of 371 plus the 7 points remaining to make grade A

Total points for A=371+7

total points for grade A=378

90% of the course total=378

divide both sides 90

90% /90 =378/90

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100%=378/90*100

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2 years ago
12 and 1 half minus 9 and 5 12’s
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Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the re
mina [271]

Answer:

Step-by-step explanation:

integrate with respect to x

Area is symmetric so will be twice the integral from zero to 1

( I cannot seem to figure out how to make the lower limit negative in this editor)

A = 2\int\limits^1_0 {(x^2 + 3) - 4x^2} \, dx)

A = 2\int\limits^1_0 {-3x^2 + 3} \, dx

A = 6\int\limits^1_0 {-x^2 + 1} \, dx

A = 6(-⅓x³ + x)\left \| {{x=1} \atop {x=0}} \right.

A = 6((-⅓(1)³ + (1)) - (-⅓(0)³ + (0)))

A = 6(⅔)

A = 4 units²

7 0
2 years ago
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