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Alchen [17]
3 years ago
13

If a= 3 -1 5 and b= 5 3 1

Mathematics
1 answer:
tiny-mole [99]3 years ago
7 0

Answer:

det(A)=-det(B)

Step-by-step explanation:

We have two matrices A, and B.

Matrix B is obtained by swapping rows 1 and 3 of matrix A.

Whenever we swap rows in matrices, the determinants does not change but the sign changes.

Therefore

det(A)=-det(B)

Also no two rows of of both matrices are the same, therefore

det(A)≠0, and det(B)≠0

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(-y+5•3)+7.2y-9)=6.2y+n
kramer
(-y+5x3)+(7.2y-9)=6.2y+n
(-y+15)+(7.2y-9)=6.2y+n
since you're adding the two parentheses, you don't need to have them there
-y+15+7.2y-9=6.2y+n
7.2y-y +15-9 =6.2y+n
6.2y + 6 =6.2y+n
6.2y - 6.2y -n = -6
-n=-6
n=6

3 0
3 years ago
Sonia asked ten friends to pick a number between one and twenty. The picks are listed below. 15, 17, 12, 19, 10 ,12, 16, 8, 13,
jeka57 [31]
The answer is
3.1
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6 0
3 years ago
a graph show the relationship between an employee total earnings,in dollars ,and the number of hours the employee works.
True [87]
What is the question?
5 0
3 years ago
The lengths of pregnancies in a small rural village are normally distributed with a mean of 262 days and a standard deviation of
RideAnS [48]

Answer:

The range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].

Step-by-step explanation:

We are given that the lengths of pregnancies in a small rural village are normally distributed with a mean of 262 days and a standard deviation of 17 days.

Let X = <u><em>lengths of pregnancies in a small rural village</em></u>

SO, X ~ Normal(\mu=262,\sigma^{2} = 17^{2})

Here, \mu = population mean = 262 days

         \sigma = standard deviation = 17 days

<u>Now, the 68-95-99.7 rule states that;</u>

  • 68% of the data values lies within one standard deviation points.
  • 95% of the data values lies within two standard deviation points.
  • 99.7% of the data values lies within three standard deviation points.

So, middle 68% of most pregnancies is represented through the range of within one standard deviation points, that is;

[ \mu -\sigma , \mu + \sigma ]  =  [262 - 17 , 262 + 17]

                          =  [245 days , 279 days]

Hence, the range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].

5 0
3 years ago
How to solve it&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;
Dimas [21]

Answer:

y = 4 and x = 12

Step-by-step explanation:

Step by step explanation in the pic. Atleast the way I did it.

8 0
3 years ago
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