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3241004551 [841]
3 years ago
5

The inequality of the most people that can be seated in the auditorium

Mathematics
1 answer:
WINSTONCH [101]3 years ago
3 0
Let x be the number of people that can be seated.

The value of x is some number 0 or greater, such that this number is a whole number (we can't have half a person). This means that x \ge 0 which is the same as saying 0 \le x

The instructions state that we can seat up to 1200 people. This is the max capacity. We can't go over this amount. So we will also have x \le 1200 indicating that x can be less than 1200 or equal to 1200.

So putting the two inequalities together, we get 0 \le x \le 1200

Note: if you haven't learned about compound inequalities yet, then the teacher may only want x \le 1200 as the answer.
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Use the substitution method to solve this
vagabundo [1.1K]
B (2,2) the answer for your question
4 0
3 years ago
A baker puts 5 cups of fruit into each pie he bakes. he pays $0.75 for 1 cup of fruit and $2.50 for the pie crust. He sells each
kirill [66]

Answer:

He earn $40

Step-by-step explanation:

To solve this problem, we first have to calculate how much it spends to make each pie

cups of fruit = 5

5 * $0.75 = $3.75

This means that per pie he spends $ 3.75 on cups of fruit and $ 2.50 on  pie crust

If we add them together we will get how much he spends for each pie

$3.75 + $2.50 = $6.25

Now to the price that the pie sells we subtract this value to know how much you earn for each pie

$10.25 - $6.25 = $4

if he sold 10 pies we multiply this number by 10 and we will get his total profit

$4 * 10 = $40

He earn $40

3 0
3 years ago
What is the answer and how do u simplify this expression??
snow_lady [41]
To do this, you first do 3^3. this is 27.
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your answer is 1/27
8 0
3 years ago
Read 2 more answers
I need help pleaseeeee Prove that: 12^13–12^12+12^11 is divisible by 7 and 19. BTW in format ______*7*19 :D
iragen [17]

Each term has a common divisor of 12^{11}:

12^{13}-12^{12}+12^{11}=12^{11}(12^2-12+1)=12^{11}\cdot133

133 = 7*19, so the number in the blanks is 12^{11}.

3 0
3 years ago
We want to find the zeros of this polynomial:
fredd [130]

Answer:

x = -3 and x = -3/2

Step-by-step explanation:

After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:

p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>

p(x) = x^2(2x+3) <u>-9(2x+3)</u>

Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:

p(x) = (x^2 - 9)(2x+3)

Factor it once more because there's a difference of squares:

p(x) = (x+3)(x-3)(2x+3)

Now just plug in whatever makes the each bracket equal 0:

x = -3, x = 3, and x = -3/2

Those are your zeros.

8 0
2 years ago
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