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levacccp [35]
3 years ago
5

A train leaves the station at time t=0. Traveling at a constant speed, the train travels 480 kilometers in 4 hours. The function

that relates the distance traveled d to the time t is?​
Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

<u>The function that relates the distance traveled d to the time t is:</u>

<u>f(t) = 120t, where d = f(t)</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

At a constant speed, the train travels 480 kilometers in 4 hours

2. The function that relates the distance traveled d to the time t is?​

Let's write the relation as a linear equation and then we'll write it using function notation, as follows:

If the train travels 480 kilometers in 4 hours, then it will travel 120 kilometers in one hour, therefore:

d = 120t

if t = 0 ⇒ d = 0, because the train is still at the station and if t = 1 ⇒ d = 120.

Now we replace d by f (t), because d = f t):

f(t) = 120t

for any given value of t, d will be equal to t multiplied 120 times

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Answer:

(32/5, -48/5)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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Equality Properties

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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

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<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                                                                                                  2x - 32 = 2(-4x + 16)
  2. Distribute 2:                                                                                                    2x - 32 = -8x + 32
  3. [Addition Property of Equality] Add 8x on both sides:                                10x - 32 = 32
  4. [Addition Property of Equality] Add 32 on both sides:                                   10x = 64
  5. [Division Property of Equality] Divide 10 on both sides:                               x = 32/5

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                                                                               -4x + 16 = y
  2. Substitute in <em>x</em>:                                                                                                 -4(32/5) + 16 = y
  3. Multiply:                                                                                                           -128/5 + 16 = y
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