[x-(-10)]²+(y-6)²=4²
the answer is (<span>x + 10)^2 + (y – 6)^2 = 16</span>
Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
Answer:
1/3÷4=0.0833
Step-by-step explanation:
This is approximate but you can round down to 0.08!
Answer:
The answer is A.
Step-by-step explanation:
Since it is a square we are finding the area of, we are multiplying two numbers. Which means 1/3 by the power of 2.
Answer:
corresponding angles
the angles are equal
equation: 9x+8 = 4x+18
x=2
angle measurements: 26⁰
Step-by-step explanation:
solve your equation
9x+8 = 4x+18
subtract 4x from each side
5x + 8 = 18
subtract 8 from each side
5x = 10
divide by 5
x = 2
insert x=2 into original equations to make sure you get the same answer.
9(2) + 8 = 26
4(2) + 18 = 26