We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
The answer is C (working shown)
The range of possible values for the volume of the boxes would be 1200 - 1800 cubic inches
The dimensions of the rectangular cardboard boxes are given as
Case I
Length = 20 inches
breadth = 15 inches
Height = 4 inches
Volume of the rectangular cardboard box in case I = Length x breadth x breadth
= 20 x 15 x 4
= 1200 cubic inches
Similarly,
Case II
Length = 20 inches
breadth = 15 inches
Height = 6 inches
Volume of the rectangular cardboard box in case I = Length x breadth x breadth
= 20 x 15 x 6
= 1800 cubic inches
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Answer:
40.53%
Step-by-step explanation:
Here, New Value = 960÷100,000
Old Value = 190÷ 100,000
∴ 
⇒ Percentage Increase = 40.53%
Thus, percent increase in the male incarceration rate during given period is 40.53%.
Answer:
A)65 is the speed of the equation, because distance/time*speed
B)He will travel 195 Miles in 3 hours, 65*3
C)It will take around 25 minutes to reach 26 miles, since they are going 65 mph at the moment.
