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SSSSS [86.1K]
3 years ago
14

Y = -12 when x = -3 , find y when x = -1 .

Mathematics
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

y=-4

Step-by-step explanation:

If y=4x

and y=-1

y=-1×4

y=-4

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Evaluate the expression when x=3 , y=−4 , and z=−6.<br> z−2x/y
hichkok12 [17]

Answer:

9/2

distribute the value of x,y, and z, on the given questions, and then you do multiplication, next addition, lastly lowest term.

6 0
3 years ago
Solve the following inequality:<br><br> 176 + 5x ≤ 200
Flauer [41]

Answer:

Step-by-step explanation:

176+5x≤ 200

-176        -176

5x≤ 24

----------

5        5

x≤ 4.8=24/5

8 0
3 years ago
The function y = x * ln(x + e) has two distinct x intercepts. One is at x = a and the other is at x = b. The value of a + b is
Snezhnost [94]
As points, x-intercepts take the form (x,0), so to find the intercepts we can set y=0 and solve for x.

x\ln(x+e)=0\implies\begin{cases}x=0\\\ln(x+e)=0\end{cases}

From the first equation alone, we already know that x=0 is a solution, which means one intercept is (0,0).

The second equation gives

\ln(x+e)=0\implies e^{\ln(x+e)}=e^0\implies x+e=1\implies x=1-e

so that the second intercept occurs at (1-e,0).

So if a=0 and b=1-e, we have a+b=1-e, giving C as the answer.
3 0
3 years ago
Write the equations for the line parallel and the line perpendicular to the given line passing through the given point.
pashok25 [27]

Answer:

10. y=2x+1                                              y = -1/2x +1

11. y=-1/3x +6                                          y = 3x -4

12. y=-5x-18                                            y=1/5x + 14/5

Step-by-step explanation:

To write the equation of a line we must have a slope and a point. To find the slope, we use the slope from the equations for parallel lines and modify it for perpendicular lines.

10. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.   The slope here is 2. The parallel slope is 2 and the perpendicular slope is the negative reciprocal or -1/2.

Parallel                                           Perpendicular

(y-1)=2(x-0)                                       (y-1)==-1/2(x-0)          

y-1=2x                                              y-1 = -1/2 x

y=2x+1                                              y = -1/2x +1

11. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.   The slope here is -1/3. The parallel slope is -1/3 and the perpendicular slope is the negative reciprocal or 3.

Parallel                                           Perpendicular

(y-5)=-1/3(x-3)                                        (y-5)=3(x-3)          

y-5=-1/3x+1                                            y-5 = 3x - 9

y=-1/3x +6                                              y = 3x -4

12. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.   The slope here is -5. The parallel slope is -5 and the perpendicular slope is the negative reciprocal or 1/5.

Parallel                                           Perpendicular

(y-2)=-5(x--4)                                           (y-2)=1/5(x--4)          

y-2=-5(x+4)                                              y-2 = 1/5(x +4)

y-2=-5x -20                                              y-2 = 1/5x +4/5

y=-5x-18                                                    y=1/5x + 14/5


4 0
3 years ago
Solve for x &amp; y <br><br> plsssss, sorry.
andriy [413]

Answer:

\huge\boxed{x=29;\ y=51}

Step-by-step explanation:

This is Isosceles triangle (look at the picture).

We know:

All triangles have internal angles that add up to 180°

Therefore:

(x-2)+(x-2)+(4x+10)=180

combine like terms:

(x+x+4x)+(-2-2+10)=180\\\\6x+6=180\qquad|\text{subtract 6 from both sides}\\\\6x=174\qquad|\text{divide both sides by 6}\\\\x=29

(x - 2)° and 3y° are supplementary angle (Two Angles are Supplementary when they add up to 180°).

Therefore:

3y+(x-2)=180

substitute x = 29 and solve for y:

3y+(29-2)=180\\\\3y+27=180\qquad|\text{subtract 27 from both sides}\\\\3y=153\qquad|\text{divide both sides by 3}\\\\y=51

7 0
2 years ago
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