First, let's factor the equation to make it easier to solve for the intercepts:
f(x) = x² + 12x + 32
f(x) = (x + 8)(x + 4)
To find the x-intercepts of a function, set the y value (f(x)) to 0:
0 = (x + 8)(x + 4)
x = -8, -4
Similarly, to find the y-intercept, set the x values to 0:
f(x) = (0 + 8)(0 + 4)
f(x) = (8)(4)
f(x) = 32
*Note that you can see 32 as the y-intercept in the parabola's original equation
Answer:
standard form is 6x−11y=13
Hello,
I suppose you mean -1! else f(x)=f^1(x)
y=x²-81
-> x=y²-81 (exchahge x and y)
->y²=x+81 (solve for y)
![y= \sqrt{x+81} \ or \ y=- \sqrt{x+81}](https://tex.z-dn.net/?f=y%3D%20%5Csqrt%7Bx%2B81%7D%20%5C%20or%20%5C%20%20y%3D-%20%5Csqrt%7Bx%2B81%7D%20)
It is because (f^-1)(x) is not a function!
with x>=-81
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