The problem does not say anything about how many of the marbles are yellow but if you put the first one back in the bag then it is an independent probability and each one would be the same individual probability. Since the problem doesn't say and I don't know if you have it somewhere else, I'll do it as an example.

Let's say there were 6 of the 10 marbles were yellow. So the probability of the first one is 6/10 and so is the second one 6/10. To find the total probability you multiply them together 6/10*6/10=36/100=9/25

Hope that helps. If you can tell me how many yellow there are I will show the work for the specific problem.

4 0

3 years ago

Can someone check questions?

Soloha48 [4]

1
The first one is correct.

2
A hexagon has the weird property of having the radius and the side being of exactly the same length

The formula is A = 3 * sqrt(3) * a^2 / 2
where a = the side or radius
A = 3 * sqrt(3) * 5^2 / 2
A = 3 * sqrt(3) * 25 / 2
A = 1.5 * sqrt(3) * 25
A = 64.95

A <<<< Answer (the first one is the answer.)

C
This one seems so much more entailed. Do you know what the cos law is? That's what I will use to find c.

c^2 = a^2 + b^2 - 2*ab* cos(C)
C = 33 degrees
a = 2.75 miles
b = 1.32 miles

c^2 = 2.75^2 + 1.32^2 - 2 * 2.75 * 1.32 * cos(33)
c^2 = 9.3049 - 6.0887
c^2 = 3.2162
c = sqrt(3.2162) = 1.7934

Now you have to use this result to get the area. You have to use Heron's formula.

A = sqrt(s * (s - a) * (s - b) * (s - c) )
s = 1/2 the perimeter
s = 1/2 (2.75 + 1.32 + 1.7934)
s = 1/2(5.8634)
s = 2.9317
I'll finish this in the comments. I have to leave for a bit.

6 0

4 years ago