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igomit [66]
3 years ago
10

As the number of pages in a photo book increases, the price of the book also increases. There is an additional shipping charge o

f 15%. The price of a book can be modeled by the equation below, where P = the price of the book, 20 is the printing charge, 0.5 is the charge per page, and x = the number of pages:
P = (20 + 0.5x) + 0.15(20 + 0.5x)

Jennifer wants to purchase a book but only has $62.10 to spend. What is the maximum number of pages she can have in her book?

x =
pages
Mathematics
1 answer:
aev [14]3 years ago
3 0
Since the maximum budget that Jennifer has is $62.10. You can input P=62.10 so now you can start solving. 

Steps: 
62.10 = (20+0.5x)+0.15(20+0.5x)
62.10 = 20 + 0.5x + 3 + 0.075x
(Combine "like" terms: so for here you combine x together)
62.10 = 0.575x + 20 +3
62.10 = 0.575x + 23
-23                    - 23
39.10 = 0.575x
(Now divide 0.575 on both sides.)
\frac{39.10}{.575} =  \frac{.575x}{.575}
You should end up with: 
x = 68

Jennifer can have 68 pages in her book to fit her budget.

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Lines c and d are parallel. Parallel lines c and d are cut by transversals s and t. Clockwise from top left, the angles formed b
lys-0071 [83]

Answer:

Options (1), (2) and (5) are true.

Step-by-step explanation:

Option (1). m∠1 = (2x + 10)°

lines c and d are the parallel lines and t is a transverse.

Therefore, m∠1 = (2x + 10)° [corresponding angles]

This option is true.

Option (2). m∠3 = 87°

Since ∠3 and angle having measure equal to 87° are the vertical angles therefore, both the angles will be equal in measure.

This option is true.

Option (3). m∠2 = (2x + 10 + 5x - 1)°

m∠2 = (5x - 1)° [Since both the angles are interior alternate angles]

Therefore, this option is not true.  

Option (4). m∠1 + m∠2 = m∠3

(5x - 1) + (2x + 10) + 87 = 180° [Sum of liner angles at a point is 180°]

7x + 96 = 180

7x = 180 - 96

x = \frac{84}{7}

x = 12

Therefore, m∠1 = (2x + 10) = 34°

                 m∠2 = (5x - 1) = 59°

                 m∠3 = 87°

For the given relation,

m∠1 + m∠2 = m∠3

34 + 59 = 87

93 = 87

Not true.

Therefore, this option is not correct.

Option (5). 87 + 2x + 10 + 5x - 1 = 180°

True.

Since these angles are the linear angles so the sum of all angles = 180°

Therefore, the given option is correct.

Options (1), (2) and (5) are the true.

4 0
3 years ago
If 3 is related to 4 then 8 is related to<br>​
tatyana61 [14]

Answer:

9 most likely

Step-by-step explanation:

This is because 3 is one away from 4, so 8 is one away from 9.

4 0
3 years ago
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An instructor has graded 23 exam papers submitted by students in a class of 24 students, and the average so far is 67. (The maxi
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Answer:

(oo) ========8

Step-by-step explanation:

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4 years ago
What fraction of £1 is seventy pence?
Veronika [31]
The answer is:  "7/10" .
________________________
  Note:  £1 = 100 pence
 
70/100 = (70÷10)/(100÷10) = 7/10 .
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4 0
4 years ago
Using elimination method
bogdanovich [222]

Answer:

The value of x is 2 and y is (-5)

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • -7x + y = – 19
  • -2x + 3y = – 19
<h3><u>To </u><u>Find</u>;</h3>
  • The value of x and y
<h3><u>B</u>y<u> </u><u>Usin</u>g<u> </u><u>Elimination</u><u> </u><u>Method</u>;</h3>

First name the equation

  • -7x + y = – 19 ...(1)
  • -2x + 3y = – 19 ...(2)

Now, Multiply equation (1) by 3 we get,

3 × (-7x + y = – 19)

-21x + 3y = – 57

Now, Eliminate

-21x + 3y = – 57

-2x + 3y = – 19

<u>+</u><u> </u><u> </u><u> </u><u> </u><u>–</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>+</u><u> </u><u> </u><u> </u><u> </u>

-19x = -38

x = -38/-19

x = 2

Now, Put the value of x in equation (2) we get the value of y.

-7x + y = – 19

-7(2) + y = – 19

-14 + y = -19

-14 + 14 + y = -19 + 14

y = -5

Thus, The value of x is (-5) and the value of y is 2.

<h3><u>For </u><u>Verification</u>;</h3>

-7x + y = – 19

-7(2) + (-5) = – 19

-14 – 5 = – 19

-19 = -19

-2x + 3y = – 19

-2(2) + 3(-5) = – 19

-4 – 15 = – 19

-19 = -19

Here, L.H.S = R.H.S

Hence Verified!

<u>-TheUnknownScientist 72</u>

4 0
2 years ago
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