Ok for this problem, there are 2 equations representing hall A and hall B
hall A: y=76x+862 where x=number of dinners and y=total cost
hall B: y=75x+894 for the same variables
To find where the 2 meet, simply substitute one equation into the other, creating: 76x+862=75x+894
Solving this, we find that x=32, so at 32 guests, the cost would be the same
For part 2, put the answer for part 1 into either equation from the start, so y=76(32)+862, or y=3294
And we already found that x=32, which represents the # of guests
Answer:
C or D
Step-by-step explanation:
Answers: (B) (2, -1) and (D) (5, 2)
<u>Step-by-step explanation:</u>
Inverse is when the x's and y's are swapped
Given: (-2, 5), (-1, 2), (0, 1), (2, 5)
Inverse: (5, -2), (2, -1) (1, 0), (5, 2)
Complete the table of values for the function f(x) = (1/3)x for a, b, and c. x : -2, -1, 0, 1, 2. f(x) : a, b, c, 1/3, 1/9
balu736 [363]
Given:
The function is
To find:
The missing values for a, b, and c in the given table.
Solution:
We have,
At x=-2,
![\left[\because \left(\dfrac{a}{b}\right)^{-n}=\left(\dfrac{b}{a}\right)^{n}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cleft%28%5Cdfrac%7Ba%7D%7Bb%7D%5Cright%29%5E%7B-n%7D%3D%5Cleft%28%5Cdfrac%7Bb%7D%7Ba%7D%5Cright%29%5E%7Bn%7D%5Cright%5D)
At x=-1,
At x=0,
![\left[\because a^0=1, a\neq 0\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20a%5E0%3D1%2C%20a%5Cneq%200%5Cright%5D)
Therefore, the missing values of a,b and c are 9, 3, and 1 respectively.
15(x+2y) .…....….…….............
