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3 years ago

Given x-8>-3 choose the selection set

Mathematics

2 answers:

kykrilka [37]3 years ago

6 0

Answer:

x > 5

Step-by-step explanation:

x-8>-3

Add 8 to each side

x-8+8>-3+8

x > 5

Alinara [238K]3 years ago

3 0

Answer:

$\large\boxed{x>5\to x\in(5,\ \infty)}$

Step-by-step explanation:

$x-8>-3\qquad\text{add 8 to both sides}\\\\x-8+8>-3+8\\\\x>5$

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the temperature is 75 degrees fahrenheit. if the temperature decreases 15 degrees, what is the new temperature

lisabon 2012 [21]

Answer: 60 degrees!

Step-by-step explanation:

75 - 15 = 60

7 0

3 years ago

What is the minimum value for h(x)=x^2−16x+60? Enter your answer in the box.

Dominik [7]

-58.

To get this, first use the equation -b/2a. This will first find the maximum. After you find the maximum, input the answer into the original equation and solve for the minimum.

Hope this helps!

4 0

3 years ago

Read 2 more answers

Calculus Problem

Roman55 [17]

The two parabolas intersect for

$8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2$

and so the base of each solid is the set

$B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}$

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, $|x^2-(8-x^2)| = 2|x^2-4|$ . But since -2 ≤ x ≤ 2, this reduces to $2(x^2-4)$ .

a. Square cross sections will contribute a volume of

$\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x$

where ∆x is the thickness of the section. Then the volume would be

$\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}$

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

$\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x$

We end up with the same integral as before except for the leading constant:

$\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx$

Using the result of part (a), the volume is

$\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}$

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

$\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x$

and using the result of part (a) again, the volume is

$\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}$

7 0

2 years ago

Apple weights in an orchard are normally distributed. from a sample farmer fred determines the mean weight of a box of apples to

Serjik [45]

<span>Mean = 270 Standard deviation = 10 x = 255 Formula for z-score, z = (x - mean)/SD z = (255 - 270) / 10 => z = -15 / 10 => z = -1.5 So by referring to z-table, -1.5 correlates to 0.0668 that implies to 0.07 So 7% of the boxes of Apples weight less than 255oz. The percentage of boxes is in the range of 255 oz and 270 oz, Now calculating the requiring percentage 50% - 7% = 43%</span>

7 0

3 years ago

Read 2 more answers

Which can be used to expand the expression below?

KiRa [710]

Answer:

Distributive Property

Step-by-step explanation:

We have

5(3x - 6/7)

Distributive Property would work because 5 has to be mutliplied by 3x and -6/7 to rid the parenthesis and also give a final answer for the equation. Any others will lead to a wrong answer.

7 0

3 years ago

Read 2 more answers