Question

Factor the polynomial function over the complex numbers.

Answer 1

Answer:

$[x - 1][x + 1][{x}^{2} + 4]$

Step-by-step explanation:

Knowing that you have to find two numbers that when they differ to 3, they also multiply to −4, and those numbers are −1 and 4. So, after clearing that up, you will have this [since our degree of this polynomial function is 4]:

$[{x}^{2} - 1][{x}^{2} + 4]$

Then, since ${x}^{2} - 1$ is factorable, you will get this:

$[x - 1][x + 1]$

Finally, attach $[{x}^{2} + 4]$ to the partially factored polynomial to get this:

$[x - 1][x + 1][{x}^{2} + 4]$

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